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zvonat [6]
4 years ago
5

If we have a normally distributed sample of ages ranging from 1 to 99 years, and we draw a score at random from this distributio

n, which of the following scores would we be most likely to draw?
A - 9
B - 22
C - 47
D - 86
Mathematics
1 answer:
svp [43]4 years ago
3 0

Answer:

C - 47

Step-by-step explanation:

In a normal distribution, the values are clustered around the center of curve. The center of the curve is the mean value of the distribution. As we go side ways the number of values decrease with respect to the mean.

A normal distribution is symmetric, the left and right hand side about the mean looks identical.

It is given in the problem that sample of ages follow normal distribution and the range is 1 to 99 years. The mean would most likely to be somewhere close to 50. Now lets assume that the mean of the distribution is indeed 50. Then it means that the number of people having age 50 would be greater than other ages. The number of people having ages 1 or 99 would be least. The closest number to 50 is 47 therefore, 47 is most likely to be drawn if we randomly draw one sample.  

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Select the correct answer from each drop-down menu.
kompoz [17]

Answer: B has greater spread than A.

Step-by-step explanation:

Since we have given that

Set A: {38, 12, 23, 48, 55, 16, 18}

Range of A = Highest - Lowest

Range of A =  55  -  12

Range of A = 43

Set B:{44, 13, 24, 12, 56}

Range of B = Highest - Lowest

Range of B =    56      -     12

Range of B =       44

Since Range of B is more than range of A.

Hence, B has greater spread than A.

6 0
4 years ago
WILL MARK BRANLIEST AND THANK! 10 POINTS, EASY QUESTION!!
elena-14-01-66 [18.8K]

Answer: 2±√3 and 1/(2±√3)

This might seem wrong, but you'll understand when you read the explanation.

Step-by-step explanation:

For this problem, you can write 2 equations to find the two numbers. Let's establish x for the first number and y for the second number.

Equation 1:

x+y=4

This equation comes from the problem that says the 2 numbers add up to 4.

Equation 2:

x*y=1

This equation comes from the part that says multiplies to 1.

Even if the problem states that the numbers can be negative, it is tricking us. We know in order for the product of 2 numbers to be positive, it has to be +*+ or -*-. Since the added numbers have to be +4, we know we cannot use -1 and 1 as our answer. What we can do is to use substitution to solve for x and y.

x+y=4 becomes y=4-x

We can substitute this into equation 2.

x(4-x)=1

4x-x²=1

4x-x²-1=0

-x²+4x-1=0

Since this equation is not factorable, we use the quadratic equation, \frac{-b±\sqrt{b^2-4ac} }{2a} (<em>Please ignore the weird looking A that's in front of the ± sign. I don't know what's wrong with the system, but it's not supposed to be there)</em>

We plug our a, b, c into the equation and get x=2±√3.

Now that we know our x, we can plug it into any of the above equations.

(2±√3)(y)=1

y=1/(2±√3)

Our final 2 numbers are 2±√3 and 1/(2±√3)

4 0
3 years ago
7th grade math help me pleaseeee
Nina [5.8K]

Answer:

Yes I agree with Andre's method he did it the correct way

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP! NO LINKS! TEN POINTS!<br><br> please explain it if you can!
Nata [24]
I think the answer would be 112cm.

To find the area of the triangle you need to do basexheight divided by 2.
8x10 divided by 2 = 40

To find the area of the rectangle
12x6=72

40+72= 112cm

I’m not sure if it’s right but I hope this helps.
7 0
3 years ago
Read 2 more answers
I need first one and the second one please! I need it tomorrow!
ArbitrLikvidat [17]
I have a total of 11 pencils = total outcome
a- since we have 6 Red, P(Red)=6/11
b- P(Black) = 3/11
c- P(Green) = 1/11
For the dice:
Total outcome 6 so :
P(3) =1/6
P(1) =1/6
P(less than5) means P( of 1 OR 2 OR 3 Or 4)
Since we have "OR" it means we can add the P(probabilities)====>
P( of 1 OR 2 OR 3 Or 4)=1/6+1/6+1/6+1/6=
= 4/6 = 2/3
5 0
3 years ago
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