(4,4)(-6,4)...notice how ur y coordinates on both of ur points is the same...that means u have a horizontal line with a slope of 0....the equation would be
y = 4.....but in point slope form...not 100% sure
y - y1 = m(x - x1)
slope(m) = 0
using (4,4)...x1 = 4 and y1 = 4
now sub
y - 4 = 0(x - 4) <==
y - y1 = m(x - x1)
slope(m) = 0
using (-6,4)...x1 = -6 and y1 = 4
sub
y - 4 = 0(x - (-6) =
y - 4 = 0(x + 6) <==
First find the the value of t where the curve intersects the Y-axis. This is when x = 0.
x = t^2 - 2t = 0 = t(t - 2)
So t= 0 and t = 2
dA = (0 - x)*dy .... Since the curve has negative x in this region
y = SQRT(t) and dy = [(1/2)/SQRT(t)]dt
dA = [2t - t^2][(1/2)/SQRT(t)]dt
dA = [t^(1/2) - (1/2)t^(3/2)]dt
Integrate to get: A = (2/3)t^(3/2) - (1/5)t^(5/2)
Now evaluate from t= 0 to t = 2.
Area = [(2/3)2^(3/2) - (1/5)2^(5/2)] - [0]
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Area = SQRT(2)[4/3 - 4/5]
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Area = SQRT(2)[8/15) = 0.754
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Answer:
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Answer:
the answer is 44cm3
Step-by-step explanation:
you're welcome
Answer:
The measure of angle BCD is
Step-by-step explanation:
step 1
Find the value of x
we know that
-----> form a straight line
substitute the values
step 2
Find the measure of angle BCD
substitute the value of x