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Alex Ar [27]
3 years ago
9

A six-sided number cube is tossed and a coin is flipped.

Mathematics
1 answer:
zhuklara [117]3 years ago
4 0
4/6 numbers are greater than 2
1/2 chance of flipping heads
Multiply the two fractions together to get the probability
1/2*4/6=2/6=1/3
1/3 probability
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Answer:

y=(x+7)2(2x+1)(x−4)

y=2x4+21x3−4x2−399x−196

Step-by-step explanation:

8 0
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The speedy punt returner and the ferocious defensive player are headed straight toward each other. The punt returner is travelin
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2

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What is −7−4p−(−5) ??
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−7−4p+5

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7 0
3 years ago
Read 2 more answers
In how many ways can a
Tomtit [17]

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.  

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = (\frac{14}{3}) = \frac{14!}{(3!(14-3)!)}

= \frac{87178291200}{(6 X 39916800)}

= \frac{87178291200}{239500800}

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

6 0
3 years ago
Kala, Deandre, and Eric have a total of $119 in their wallets, Kala has $6 more than Deandre. Eric has 3 times what kala has. Ho
Tomtit [17]
Deandre = x
Kala = x + 6
Eric = 3(x+6)
x + x + 6 + 3(x+6) = 119
2x + 6 + 3x + 18 = 119
5x + 24 = 119
5x = 95, x = 19
Deandre has $19
Kala has 19 + 6 = $25
Eric has 3(25) = $75
4 0
2 years ago
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