Answer:

Step-by-step explanation:
I am assuming that you mean
.

<em>Brainilest Appreciated.</em>
Hang on ,it is already proven through given .
So The proof is of one line only
- ray FEH bisects <DFG (Given)
Hence proved .
Answer:
2, 5, 14, 41, 122
Step-by-step explanation:
Using the recursive rule with a₁ = 2
a₂ = 3a₁ - 1 = 3(2) - 1 = 6 - 1 = 5
a₃ = 3a₂ - 1 = 3(5) - 1 = 15 - 1 = 14
a₄ = 3a₃ - 1 = 3(14) - 1 = 42 - 1 = 41
a₅ = 3a₄ - 1 = 3(41) - 1 = 123 - 1 = 122
The first 5 terms are 2, 5, 14, 41, 122
The answer is A). 23.
<span>g(x)= 2x + 3 </span>
<span>g(x) = x^2 + 1 </span>
<span>g(3) = 10 </span>
<span>f(g(3)) </span>
<span>= f(10) </span>
<span>= 23 </span>
The equation <u>6 + 9a = 51</u> can help find out how many adults were in the group.