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taurus [48]
3 years ago
8

NEED HELP RN PLZ!!!!!!!!!!!!!!!!!!!!!Complete the square to find the zeros of y=x^2+12x-5?

Mathematics
1 answer:
solmaris [256]3 years ago
3 0

Answer: -6 +/- \sqrt{41} = x

<u>Step-by-step explanation:</u>

   y = x² + 12x - 5

<u>  +5 </u>   <u>              +5 </u>

y + 5 = x² + 12x              

<u> + 36  </u>  <u>            +36 </u>           <em>added (12 ÷ 2)² to both sides</em>

y + 41 = (x + 6)²

To find the zeros, let y = 0:

0 + 41 = (x + 6)²

\sqrt{41} = (\sqrt{x+6} )^{2}

+/-\sqrt{41} = x + 6

<u>-6            </u>     <u>   -6   </u>

-6 +/- \sqrt{41} = x



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Suppose PR = 54, solve for QR<br> 4x-1<br> 3x-1<br> P<br> R
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Answer:

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Step-by-step explanation:

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