Question

clyde makes a copy of an 8 in. x 10 in. photo, reducing it to 3/4 of its size. what are the dimensions of the new photo?

Answer 1

Clyde should have applied the power of a power rule and multiplied the exponents instead of adding them. The simplified form should be j to the 16th power.

Answer 2

To get the reduced dimensions we have to multiply each dimension by 3/4 factor, so
$8 \frac{3}{4}= 2\frac{3}{1}=6$ - first dim
$10* \frac{3}{4}= \frac{30}{4}=7.5$ -second dim
Answer is  6x7.5