Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
Data:
Apples = 28
Oranges = 20
Pears = 12
<span>What is the ratio of apples to the total pieces of fruit?
Solving:
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2.836x10^-5 is going to be your answer
Answer:
it would be
B. y + 5 = 2(x + 6)
if there is a negative number and you are subtracting it turns positive
Step-by-step explanation:
Answer:
the answer would be it is approximately <u>4</u><u>3</u><u>.</u><u>8</u><u>5</u>
<u>(</u><u>did </u><u>addition</u><u>)</u>