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2 years ago

11

Once a commercial plane reaches the desired altitude, the pilot often travels at a cruising speed. On average, the cruising spee

d is 620 miles per hour. If a plane travels at this cruising speed for 8 hours, how far does the plane travel while cruising at this speed?

1 answer:

NemiM [27]2 years ago

7 0

Answer:

4960 miles

Step-by-step explanation:

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What is 17x13 divide by four

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Bruh u don’t no this is easy

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Pls help me guys!<br> Thanks :D

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The top right is the answer. The base should be square with lengths of 8 and the height is 10.

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Fill in the blanks below.

Dmitry_Shevchenko [17]

Answer:

a) <em>Slope of the line m = ∞</em>

<em>b) Slope of the line m =0</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<u><em>Step(i):-</em></u>

<em>Given points are ( 7,7) and (7,-8)</em>

<em>Slope of the line</em>

<em> </em> $m = \frac{y_{2} - y_{1} }{x_{2}-x_{1} }$ <em />

<em> </em> $m = \frac{-8-7 }{7-7 } = \frac{-15}{0} = infinite$ <em />

<em> m = ∞</em>

<u><em>Step(ii):-</em></u>

Given points are (-6,7) and (9,7)

<em>Slope of the line</em>

<em> </em> $m = \frac{y_{2} - y_{1} }{x_{2}-x_{1} }$ <em />

<em> </em> $m = \frac{7-7 }{9-(-6) } = \frac{0}{15} = 0$ <em />

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3 years ago

The product of 6 and 2 added to the quotient of 9 and 3

Firdavs [7]

Answer:

15

Step-by-step explanation:

Follow pemdas and multiply 6 and 2, then divide 9 and 3, finally, add the two together to get 15

6×2+9÷3

12+9÷3

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=15

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Find the point, M, that divides segment AB into a ratio of 5:2 if A is at (1, 2) and B is at (8, 16).

d1i1m1o1n [39]

Since M divides segment AB into a ratio of 5:2, we can say that M is 5/(5+2) of the length of AB. Therefore 5/7 × AB.
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5/7×(8 - 1) = 5/7 (7) = 5 for the x
and 5/7×(16 - 2) = 5/7 (14) = 10 for the y
But remember the line AB starts at A (1, 2),
so add 1 to the x: 5+1 = 6
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