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Masteriza [31]
2 years ago
10

An airplane takes 8 hours to travel a distance of 5824 kilometers against the wind. The return trip takes 7 hours with the wind.

What is the rate of the plane in still air and what is the rate of the wind?
Mathematics
1 answer:
user100 [1]2 years ago
4 0

Answer:

Speed of plane in still air = 780 km/h

Speed of air = 52 km/hr

Step-by-step explanation:

Let the speed of plane in still air = u km/h

Let the speed of air = v km/h

Against the air, the resultant speed = (u-v) km/hr

With the air, the resultant speed = (u+v) km/hr

Formula for speed is given as:

Speed = \dfrac{Distance}{Time }

Given that:

Distance = 5824 km

Time taken against the wind = 8 hours

Speed against the wind:

u-v = \dfrac{5824}{8} \\\Rightarrow u-v = 728 ...... (1)

Time taken with the wind = 7 hours

Speed with the wind:

u+v = \dfrac{5824}{7} \\\Rightarrow u+v = 832 ...... (2)

Adding (1) and (2):

2u=1560\\\Rightarrow u = 780\ km/hr

By equation (1):

780-v=728\\\Rightarrow v = 52\ km/hr

Speed of plane in still air = 780 km/h

Speed of air = 52 km/hr

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