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pickupchik [31]
2 years ago
15

On they playground 1/4 of the 5th graders students are on the jungle gym and 1/3 of the of the 5th graders students were playing

kickball. What part of the 5th grade students were not on the jungle gym or playground
Mathematics
1 answer:
maria [59]2 years ago
8 0

Answer:

\frac{5}{12}  part of the 5th grade students were not on the jungle gym or playground.

Step-by-step explanation:

Given:

On the playground 1/4 of the 5th graders students are on the jungle gym and 1/3 of the of the 5th graders students were playing kickball.

Now, to find part of the 5th grade students who were not on the jungle gym or playground.

Total part of students assume to be whole = 1.

Part of students on the playground = \frac{1}{4}.

Part of students on the jungle gym = \frac{1}{3}.

Now, to get the part of the 5th grade students not on the jungle gym or playground by subtracting part of students on the playground and on the jungle gym from the whole part:

1-(\frac{1}{4}+\frac{1}{3} )

=1-(\frac{4+3}{12} )

=1-\frac{7}{12}

=\frac{12-7}{12}

=\frac{5}{12} .

Therefore, \frac{5}{12}  part of the 5th grade students were not on the jungle gym or playground.

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Answer:

(0.5, 0.5)

Step-by-step explanation:

Use the midpoint formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

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2 years ago
A cylindrical container of height 28cm and diameter 18cm is filled with water.The water is then poured into another container wi
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Answer:

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Asked on December 20, 2019 by

Ziya Vïvəķ

A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

MEDIUM

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

2

56

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

2

h=32×22×14 cm

3

7

22

×(28)

2

×h=9856 cm

h=

22×784

9856×7

cm

h=4 cm

4 0
3 years ago
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Use SOHCAHTOA for this. Work out 'm' in 3sf, I need the working out.
Lady bird [3.3K]

Anwer:3.537m

STEP BY STEP EXPLANATIOND:using SOH CAH TOA

First find the opposite

Represent the opposite with x

Tan 33° =x\10

x=10Tan 33°

x=6.494

To find m

Sin 33°=m\6.494 Sin 33°

m=3.5368

m=3.537meteres

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3 years ago
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2 years ago
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Answer:

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V=7×4×24=672m³

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