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pickupchik [31]
3 years ago
15

On they playground 1/4 of the 5th graders students are on the jungle gym and 1/3 of the of the 5th graders students were playing

kickball. What part of the 5th grade students were not on the jungle gym or playground
Mathematics
1 answer:
maria [59]3 years ago
8 0

Answer:

\frac{5}{12}  part of the 5th grade students were not on the jungle gym or playground.

Step-by-step explanation:

Given:

On the playground 1/4 of the 5th graders students are on the jungle gym and 1/3 of the of the 5th graders students were playing kickball.

Now, to find part of the 5th grade students who were not on the jungle gym or playground.

Total part of students assume to be whole = 1.

Part of students on the playground = \frac{1}{4}.

Part of students on the jungle gym = \frac{1}{3}.

Now, to get the part of the 5th grade students not on the jungle gym or playground by subtracting part of students on the playground and on the jungle gym from the whole part:

1-(\frac{1}{4}+\frac{1}{3} )

=1-(\frac{4+3}{12} )

=1-\frac{7}{12}

=\frac{12-7}{12}

=\frac{5}{12} .

Therefore, \frac{5}{12}  part of the 5th grade students were not on the jungle gym or playground.

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Evaluate the expression: -6 ( -3/12 ) ( -4 ) ( 5) divided by ( 10 ) <br><br> Please show your work
blagie [28]

Answer:

-3

Step-by-step explanation:

firstly, -3/12 is not in the simpliest form so we have to simplified it:

-3/12 / 3 = -1/4, now we got:

= (-6*(-1/4)*-4*5) / 10

The upper part of the equation: (-6*(-1/4)*-4*5) can be simplified as:

((-6*-1*-4*5) / 4) / 10

= (-120/4)/10

= -30 / 10

= -3

Hope this help you :3

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Step-by-step explanation:

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