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Alchen [17]
3 years ago
11

In a study of the gasoline mileage of model year 2017 automobiles, the mean miles per gallon was 27.5 and the median was 26.8. T

he smallest value in the study was 12.70 miles per gallon, and the largest was 50.20. The first and third quartiles were 17.95 and 35.45 miles per gallon, respectively. Determine the type of skewness.
Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

This is skewed torwards the right. Or in other words positively skewed distribution.

Step-by-step explanation:

All of the values are fairly close together torwards the lower range. While 50.20 is more of an outlier, so this graph would gradualy skew to the right.

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Step-by-step explanation:

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Svet_ta [14]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Tcecarenko [31]
I think that B is the most logical answer.


3 0
3 years ago
54% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability
Degger [83]

Part B is not clear and the clear one is;

P(X ≥ 6)

Answer:

A) 0.238

B) 0.478

C) 0.114

Step-by-step explanation:

To solve this, we will make use of binomial probability formula;

P(X = x) = nCx × p^(x)•(1 - p) ^(n - x)

A) 54% of U.S. adults have very little confidence in newspapers. Thus;

p = 0.54

10 random adults are selected. Thus;

P(X = 5) = 10C5 × 0.54^(5) × (1 - 0.54)^(10 - 5)

P(X = 5) = 0.238

B) P(X ≥ 6) = P(6) + P(7) + P(8) + P(9) + P(10)

From online binomial probability calculator, we have;

P(X ≥ 6) = 0.2331 + 0.1564 + 0.0688 + 0.01796 + 0.0021 = 0.47836 ≈ 0.478

C) P(x<4) = P(3) + P(2) + P(1) + P(0)

Again with online binomial probability calculations, we have;

P(x<4) = 0.1141 ≈ 0.114

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