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cestrela7 [59]
3 years ago
11

Suppose a list A contains the 30 students in a mathematics class, and a list B contains the 35 students in an English class, and

suppose there are 20 names on both lists. Find the number of students: (a) only on list A, (b) only on list B, (c) on list A or B (or both), (d) on exactly one list.
a. List A has 30 names and 20 are on list B; hence 30 - 20 =10 names are only on list A.
b. Similarly, 35 -20 =15 are only on list B.
c. We seek n(A U B). By inclusion—exclusion,
n(AU B) = n(A) +n(B)- n(A⋂ B) = 30+35 -20 —45.
In other words, we combine the two lists and then cross out the 20 names which appear twice.
d. By (a) and (b), 10 + 15= 25 names are only on one list; that is, n(A⊕ B)= 25.

Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0

Answer:

(a)10

(b)15

(c)45

(d)25

Step-by-step explanation:

You can use the attached Venn diagram for illustration.

n(A)=30

n(B)=35

n(A⋂B)=20

(a) Studentsbonly on list A

n(A only)= n(A)-n(A⋂B)=30-20=10

(b)Students only on list B

n(B only)= n(B)-n(A⋂B)=35-20=15

(c)Students on list A or B (or both)

This is the total number of students in the class.

n(AUB)

= n(A only) +n(B only)+ n(A⋂ B)

= 10+15 + 20 = 45

(d)Students on exactly one list.

n(on exactly one list)

= n(A only) +n(B only)

= 10+15

=25

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Answer:

x+63 = 90

x = 27

Step-by-step explanation:

The two angles are complementary, so they add to 90 degrees

x+63 = 90

Subtract 63 from each side

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x = 27

7 0
3 years ago
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CaHeK987 [17]

Answer:

Trick question ;)

Step-by-step explanation:

The misdirection in this riddle is in the second half of the description, where unrelated amounts are added together and the listener assumes those amounts should add up to 30, and is then surprised when they do not ⁠— ⁠there is, in fact, no reason why the (10 ⁠− ⁠1) ⁠× ⁠3 ⁠ + ⁠2 ⁠ = ⁠29 sum should add up to 30.

The exact sum mentioned in the riddle is computed as:

SUM = $9 (payment by Guest 1) +

          $9 (payment by Guest 2) +

          $9 (payment by Guest 3) +

          $2 (money in bellhop's pocket)

The trick here is to realize that this is not a sum of the money that the three people paid originally, as that would need to include the money the clerk has ($25). This is instead a sum of a smaller amount the people could have paid ($9 × 3 people = $27), added with the additional money that the clerk would not have needed had they paid that smaller amount ($27 paid - $25 actual cost = $2). Another way to say this is, the $27 already includes the bellhop's tip. To add the $2 to the $27 would be to double-count it. So, the three guests' cost of the room, including the bellhop's tip, is $27. Each of the 3 guests has $1 in his pocket, totalling $3. When added to the $27 revised cost of the room (including tip to the bellhop), the total is $30.

To obtain a sum that totals to the original $30, every dollar must be accounted for, regardless of its location.

Thus, the sensible sum that we really desire is this one:

$30 = $1 (inside Guest pocket) +

        $1 (inside Guest pocket) +

        $1 (inside Guest pocket) +

        $2 (inside bellhop's pocket) +

        $25 (hotel cash register)

This sum does indeed come out to $30.

To further illustrate why the riddle's sum does not relate to the actual sum, we can alter the riddle so that the discount on the room is extremely large. Consider the riddle in this form:

Three people check into a hotel room. The clerk says the bill is $30, so each guest pays $10. Later the clerk realizes the bill should only be $10. To rectify this, he gives the bellhop $20 to return to the guests. On the way to the room, the bellhop realizes that he cannot divide the money equally. As the guests didn't know the total of the revised bill, the bellhop decides to just give each guest $6 and keep $2 as a tip for himself. Each guest got $6 back: so now each guest only paid $4; bringing the total paid to $12. The bellhop has $2. And $12 + $2 = $14 so, if the guests originally handed over $30, what happened to the remaining $16?

Now it is more obvious that the question is quite unreasonable. One cannot simply add a couple of payments together and expect them to total an original amount of circulated cash.

More economically, money is accounted by summing together all paid amounts (liabilities) with all money in one's possession (assets). That abstract formula holds regardless of the relative perspectives of the actors in this exchange.

The guests of the hotel paid $27, but also have $3 among their pockets at the story's end. Their assets are $3, and their liabilities are $27 ($30 = 27 + 3). Thus, the original total is accounted.

From the perspective of the hotel clerk, the hotel has $25 in assets and lost $5 in liabilities ($30 = 25 + 5).

From the perspective of the bellhop, his assets are $2, and his liabilities are $3 to guests and $25 to the register at the desk ($30 = 2 + 3 + 25).

To illustrate the issue through equations:

1) 10 + 10 + 10 = 30

2) 10 + 10 + 10 = 25 + 2 + 3

3) 10 + 10 + 10 - 3 = 25 + 2 + 3 - 3 (adding -3 to both sides of the equation to cancel out the +3 on the right side)

4) 10 - 1 + 10 - 1 + 10 - 1 = 25 + 2

5) 9 + 9 + 9 = 25 + 2 (obs: tip to bellhop has already been paid)

6) 27 = 27

How the riddle is deceptive comes in line 8:

7) 9 + 9 + 9 = 25 + 2

8) 9 + 9 + 9 + 2 = 25 (pushing +2 to the other side without inverting the sign)

9) 27 + 2 = 25

10) 29 != 25

How it should be:

7) 9 + 9 + 9 = 25 + 2

8) 9 + 9 + 9 -2 = 25 + 2 -2 (adding -2 to both sides of the equation to cancel the +2 on the right side, which means the bellhop returned the tip or gave a discount of $2)

9) 9 + 9 + 9 - 2 = 25

10) 27 - 2 = 25

11) 25 = 25

The puzzle should subtract the bellhop's tip from the $27 rather than add it.

4 0
4 years ago
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algol13
Hello!! Lets do this step by step! :) 
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And we get our answer!
x=5
y=2

Hope that helps! If you have any other questions or need further explanation just let me know! :)

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