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2 years ago

Find the area: look at pic

Mathematics

1 answer:

Anika [276]2 years ago

7 0

Answer:

15in

Step-by-step explanation:

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Find the discount rate

kifflom [539]

we'd do the same as before on this one as well.

if we take 27.99 to be the 100%, what is 12 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 27.99&100\\ 12&x \end{array}\implies \cfrac{27.99}{12}=\cfrac{100}{x}\implies 27.99x=1200 \\\\\\ x=\cfrac{1200}{27.99}\implies x\approx 42.87$

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3 years ago

Help! Quadrilateral ABCD is rotates 90 clockwise about the origin. What are the coordinates of quadrilateral A’B’C’D?

stepladder [879]

Answer:

its a i had this on my test

3 0

3 years ago

Read 2 more answers

What is the equation of the line that passes through the point (-6,-8) and has a slope of 1/3

Arturiano [62]

y + 8 = 1/3 (x+6)

With the given information, we can use the point-slope formula, , to write the equation of the line. Substitute values for the , , and in the formula to do so.

The represents the slope, so substitute in its place. The and represent the x and y values of one point the line intersects, so substitute -6 for and -8 for . This gives the following answer and equation (just make sure to convert the double negatives into positives:

8 0

2 years ago

19 is 25% of what number?

zepelin [54]

Answer:

19/25 * 100 = 76%

Step-by-step explanation:

3 0

3 years ago

The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation

Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

Let X = weights of adult male birds of a certain species

So, X ~ Normal( $\mu=27.5,\sigma^{2} =1.1^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{ X-\mu}{\sigma } }$ ~ N(0,1)

where, $\mu$ = population mean weight = 27.5 grams

$\sigma$ = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

Z score = $\frac{ X-\mu}{\sigma } }$ = $\frac{ 29.37-27.5}{1.1 } }$

= 1.7

4 0

2 years ago