The answer is 3 // The ones in blue are the domain and the ones in red are the range
Answer:
Correct answer: x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
Step-by-step explanation:
Given:
3 x⁴ + 14 x² - 5 = 0 biquadratic equation
this equation is solved by a shift x² = t and get:
3 t² + 14 t - 5 = 0
t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6
t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6
t₁ = -5 or t₂ = 1 / 3
the solution t₁ = -5 is not accepted because it cannot be x² = -5
we accepted t₂ = 1 / 3
x² = 1 / 3 ⇒
x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
God is with you!!!
Answer:
-320 i guess
Step-by-step explanation:
51*-2*3-21+7=-320
(x-5)(x+3)=0
x^2+3x-5x-15=0
(x^2+3x) (-5x-15)
x(x+3) -5(x+3)
x-5=0 x+3=0
x=5 OR -3
Answer:
a
Step-by-step explanation:
because i got it right
