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Anna11 [10]
3 years ago
13

M is between L and C. LM = 11, MC = 2x + 5, and LC = 6x – 6. What is MC?

Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0
I hope this helps you

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What does that even mean
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When factoring x2 – 3xy + 2y2 by grouping the first step can be:
blagie [28]

Answer:

x^2 – 3xy + 2y^2

Step-by-step explanation:

Factor the following:

x^2 - 3 x y + 2 y^2

Hint: | Factor the quadratic x^2 - 3 x y + 2 y^2.

The factors of 2 that sum to -3 are -1 and -2. So, x^2 - 3 x y + 2 y^2 = (x - 1 y) (x - 2 y):

Answer:  (x - y) (x - 2 y)

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There are 25 scented candles left in stock on eBay. On amazon there are 12 + (9x3) scented candles left. How many scented candle
oksano4ka [1.4K]
(9x3)= 27 +12= 39. 39 is the answer
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3 years ago
Divide. <br> 3/5 \1/4<br><br> A. 3/20<br> B. 5/12<br> C. 4/9<br> D. 2 2/5
KIM [24]
Its letter A 3/20 i divided it


4 0
3 years ago
A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
Vanyuwa [196]

Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

To Find:

Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

And height will be x

V(x)=x*(26-x)*(13-x)

To get maximum volume differentiate the above equation,

V(x)=x*(26*13-26*x-13*x+x^2)

V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

x=[-b±(b^2-4ac)^1/2]/2a

x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

x=22.17  or x=3.8288

Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

6 0
3 years ago
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