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Brrunno [24]
3 years ago
6

Marcie wants to simplify this expression. Which like terms can she combine? 12 - 4x 3 A) -4x and 3 B) 12 and 3 C) 12 and -4x D)

12, -4x, and 3
Mathematics
1 answer:
mariarad [96]3 years ago
6 0
Its B like terms she can combine are 12 and 3 simply because there are no numbers with -x
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Solve the following system by any method -8x-8y=0 -8x+2y=-20
iVinArrow [24]
                     \fbox{Solution by using Matrix} 

\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20

\text{Rewrite the linear equations above as a matrix} 

\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right] 

\text{Apply to Row2 : Row2 + Row1} 

\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right] 

\text{ Simplify rows} 

\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right] 

\text{Note: The matrix is now in echelon form.}\text{The steps below are for back substitution.} 

\text{Apply to Row1 : Row1 + 8 Row2} 

\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right] 

\text{ Simplify rows}  

\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right] 

\text{Therefore, the solution is} 

x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}
7 0
3 years ago
Math lottssssss offf points
yan [13]
Constant of Proportionality = d/t = 90/2 = 45 mph

In short, Constant of Proportionality would be: 45 miles per hour.

Here, d/t = 45
d = 45t

In short, Your Equation would be: d= 45t

Hope this helps!


5 0
3 years ago
Grace, Chelsea, and Roan are simplifying the same polynomial expression. which students work is correct and why?
Trava [24]

Answer:

Grace

Step-by-step explanation:

Chelsea and Roan didn't distribute the negative sign in the second half of the first expression.

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-2(x) + (-2)(-8)

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8 0
3 years ago
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DanielleElmas [232]

Answer:

3x-2y=-6

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6 0
3 years ago
What is the product of 2x + y and 5x – y + 3?
hoa [83]

Answer:  The required product is 10x^2-y^2+3xy+6x+3y.

Step-by-step explanation:  We are to find the product f the following two algebraic expressions:

E_1=2x+y,\\\\E_2=5x-y+3.

To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.

The multiplication is as follows:

M\\\\=E_1 \times E_2\\\\=(2x+y)\times(5x-y+3)\\\\=10x^2-2xy+6x+5xy-y^2+3y\\\\=10x^2-y^2+3xy+6x+3y.

Thus, the required product is 10x^2-y^2+3xy+6x+3y.

7 0
3 years ago
Read 2 more answers
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