How do you write 72 percent as a fraction, mixed number, or whole number in simplest form?

1 answer:

8 0

72%=72/100
To simplify 72/100 you have to divide by the greatest common factor of both numbers, in this case 4. 72÷4=18, 100÷4=25. Therefore your answer of 72/100 in simplest form is 18/25

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A PE teacher is charting the weight and BMI of her students. The table below shows the measured weight for all of her students f

svetlana [45]

Answer:

122.67 average

Step-by-step explanation:

Mean = (every value added up)/(# of values)

Mean = (105 + 2(110) + 2(112) + 3(113) + 2(115) + 5(116) + 4(117) + 7(118) + 5(120) + 5(121) + 4(125) + 5(126) + 2(128) + 130 + 3(132) + 134 + 3(135) + 2(140) + 2(141) + 150)/60

= 7360/60

= 122.67

I had trouble understanding the data but I hope I did this right!

6 0

3 years ago

Han and Tyler are following a polenta recipe that uses 5 cups of water for every 2 cups of cornmeal.

Aleonysh [2.5K]

Answer:

Step-by-step explanation:

1. 5 cups of cornmeal=2 cups of water. Using 115 cups of cormeal would mean you need 287.5 cups of water, not 3.

3 is too little

2: If you use 5 cups of water for every 3 cups of cornmeal, for 3 cups of cornmeal you'd need like 6.5 cups of water, not that high of a number.

5 0

4 years ago

Read 2 more answers

What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)

lbvjy [14]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}$

$BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}$

$DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89$