Answer:
Step-by-step explanation:


+6 +6

You can't go any further s its b, NO SOLUTION.
Hope this helps :)
Answer:
240 houses
Step-by-step explanation:
Given that:
Number of streets = 4
Length of each street = 3/4 miles long
Street is divided into lots with one house built per lot
1 mile = 5289 feets
3/4 miles = (3/4) * 5280 = 3960 feets
Hence, street is 3960 feets long
Since each lot must have at least 65 feet frontage along the street:
Number of lots per street :
Length of street / frontage length
3960 ft / 65 ft = 60.92
Hence, maximum number of lots per street = 60 lots per street
Maximum number of houses in New neighborhoods :
Number of lots per street × number of streets
= 60 × 4
= 240 houses
Answer:
2. (-3f)
3. (4f)
4. x - 11 (not sure if this one is correct)
Step-by-step explanation:
Move -3 to the left of f = -3f
Move 4 to the left of f = 4f
f(x)=x+11 f ( x ) = x + 11
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
Isometry is defined as the <span> transformation that is invariant with respect to the distance
The statement that is true for isometry that is corrrect is
</span><span>The preimage and the image are congruent.
</span>so correct option is A as both the preimage and image are congruent
hope it helps<span />