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otez555 [7]
2 years ago
15

Simplify fully

title="\frac{4x^{2} +4x}{2x^{2} -2}" alt="\frac{4x^{2} +4x}{2x^{2} -2}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Tatiana [17]2 years ago
5 0

Answer:

\frac{2x}{x-1}

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A random sample of 20 purchases showed the amounts in the table (in $). The mean is $49.57 and the standard deviation is $20.28.
son4ous [18]

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The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

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Now, find M as such

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The lower end of the interval is the mean subtracted by M. So it is 49.57 - 12.17 = $37.40.

The upper end of the interval is the mean added to M. So it is 49.57 + 12.17 = $61.74.

The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

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