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2 years ago

15

Simplify fully

title="\frac{4x^{2} +4x}{2x^{2} -2}" alt="\frac{4x^{2} +4x}{2x^{2} -2}" align="absmiddle" class="latex-formula">

1 answer:

Tatiana [17]2 years ago

5 0

Answer:

$\frac{2x}{x-1}$

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Here are two closed containers and four balls just fit into each container. Each ball has a diameter of 60mm. Which container ha

Studentka2010 [4]

Answer:

Container B has smaller surface area.

Step-by-step explanation:

Given:

Container A

Radius = 60/2 = 30 mm

Height = 4 x 60 = 240 mm

Container B

Length = 120

Width = 120

Height = 60

Computation:

Surface area of container A (Cylinder) = 2πr[h+r]

Surface area of container A (Cylinder) = 2[22/7][60][120+60]

Surface area of container A (Cylinder) = 67,885.70 mm² (Approx)

Surface area of container B (Cuboid) = 2[lb+bh+hl]

Surface area of container B (Cuboid) = 2[(14,400)+(7,200)+(7,200)]

Surface area of container B (Cuboid) = 57,600 mm²

Container B has smaller surface area.

8 0

3 years ago

If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e

Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

<em>99 is an outlier of pet group</em>
<em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

$n = 15$

The quartiles positions are:

$Q_1 = \frac{n + 1}{4}$

$Q_1 = \frac{15 + 1}{4}$

$Q_1 = \frac{16}{4}$

$Q_1 = 4th$

$Q_3 = Q_1 \times 3$

$Q_3 = 4th \times 3$

$Q_3 = 12th$

So, we have:

$Q_1 = 4th$

$Q_3 = 12th$

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

$Q_1 = 68$

$Q_3= 79$

The lower and upper limits of the outlier are:

$L = Q_1 - 1.5 \times (Q_3 - Q_1)$

$U = Q_3 + 1.5 \times (Q_3 - Q_1)$

So, we have:

$L = 68 - 1.5 \times (79 - 68)$

$L = 51.5$

$U = 79+ 1.5 \times (79 - 68)$

$U = 95.5$

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

5 0

3 years ago

Find the sum of -2.5, -3 and 6.7

Alja [10]

The sum of -2.5, -3 and 6.7 is 1.2

4 0

3 years ago

The weight of bags of coffee beans at the grocery store follows a Normal distribution with a mean of μ = 7 ounces and a standard

aleksley [76]

Answer:

C.

Step-by-step explanation:

The random variable W is Normal, with a mean of 28 ounces and a standard deviation of four ounces.

mean of total = 7+7+7+7 = 28

Variance of total = 4+4+4+4 = 16

SD of total = sqrt(16) = 4

4 0

3 years ago

What is the y-value in the solution to this system of linear equations?

baherus [9]

Answer:

Option A.)−4

Step-by-step explanation:

we have

4x+5y=-12 -----> equation A

-2x+3y=-16 -----> equation B

Solve the system of equations by elimination

Multiply the equation B by 2

2*(-2x+3y)=-16*2

-4x+6y=-32 -----> equation C

Adds equation A and equation C

4x+5y=-12

-4x+6y=-32

-----------------

5y+6y=-12-32

11y=-44

y=-4

4 0

3 years ago

Read 2 more answers