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Blababa [14]
3 years ago
11

Mary’s grade on her research paper counts for 20% of her final grade in english. if there are a total of 400 points possible how

many points can she earn for her research paper
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
8 0

Answer:

80 points

Step-by-step explanation:

400 x 0.20% = 80

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A company makes traffic signs one of those signs can be modeled by an equilateral triangle with the perimeter of 144 inches the
barxatty [35]

Answer:

The height of the larger traffic signs is 51.96 inches

Step-by-step explanation:

Given that initially, A company makes traffic signs of an equilateral triangle with the perimeter of 144 inches

Now, A company makes similar traffic signs of perimeter 1.25 of original

New perimeter will be 1.25x144=180 inches

Let triangle ABC be a larger triangle with 180inches of the perimeter.

It is given that the triangle is an equilateral triangle,

Therefore, Side AB=BC=AC

The perimeter of a triangle ABC is

AB+BC+AC=180

3AB=180

AB=60 inches

Figure show that triangle ABC and AD is the height of the triangle.

Since, the triangle ABC is an equilateral triangle,

AD is the perpendicular bisector of BC

so that,

BD=DC and Angle ADB=90

In right triangle ADB,

Angle D =90 and Angle B =60

Side BD=60/2=30 inches and AB=60 inches

Using Pythagoras theorem,

AD^{2} +BD^{2} =AC^{2}

(AD)^{2} +(30)^{2} =60^{2}

(AD)^{2} =60^{2}-(30)^{2}

AD=51.96 inches

Thus, The height of the larger traffic signs is 51.96 inches

4 0
3 years ago
Describe fully the transformation that maps shape a and b
Fiesta28 [93]

Answer:

Rotate 90' clockwise Centre (-2, -2)

if you mean A onto B

8 0
3 years ago
Divide $210 in the ratio 2:5
RideAnS [48]
Let us say Karen received X amount of money. Then Natasha has received (X+210).
The ratio that the money divided was 2:5.
X/(X+210) = 2/5
5X = 2(X+210)
3X = 420
X = 140
Total money shared
= X+(X+210)
= 140+140+210
= 490

So the total money shared was $490.


8 0
3 years ago
100 points ! and I will mark me Brainliest
Romashka [77]

Answer:

it ARBY'S

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
Paha777 [63]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

We know that,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

Using the trigonometric ratios, we get

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Hence, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

6 0
3 years ago
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