All categories

2 years ago

The product of three consecutive numbers is 21,924. What is the smallest number out these numbers?

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

7 0

Answer:

Step-by-step explanation:

Let the middle number be x.

(x - 1)(x)(x + 1) = 21,924

You can solve that equation, or you can use logic.

The 3 numbers are going to be close to the cubic root of 21,924.

cubic root of 21,924 = 27.988 or approx 28.

Try 27, 28, 29

27 * 28 * 29 = 21,924

Answer: 27

You might be interested in

In order for the parallelogram to be a square, x=?

iren [92.7K]

Answer:

Step by step explanation

We know that the diagonals of a square bisects it's angles and every angles of square are 90°

m<BCD = 90°

m<BCA = m< DCA = 4x + 17

m<BCA + m<DCA = m <BCD

4x + 17 + 4x + 17 = 90

4x + 4x + 17 + 17 = 90

8x + 34 = 90

8x = 90 - 34

8x = 56

X = 56/8

x = 7

Hope this helps...

Good luck on your assignment...

5 0

3 years ago

Read 2 more answers

4,000 mm= how many m? Check the comments

Murrr4er [49]

Divide the length value by 1000

6 0

3 years ago

What are the solutions of this quadratic equation? 4x2 + 3 = 4x + 2

never [62]

Answer:

A. x = 1/2

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Algebra I

Terms/Coefficients
Factoring
Standard Form: ax² + bx + c = 0
Solving quadratics

Step-by-step explanation:

Step 1: Define

Identify

4x² + 3 = 4x + 2

Step 2: Solve for x

[Equality Property] Rewrite in standard form: 4x² - 4x + 1 = 0
Factor: (2x - 1)² = 0
Solve: x = 1/2

5 0

2 years ago

What is 9/1000 in its simplest form

dmitriy555 [2]

It think it 9000.......

7 0

3 years ago

Read 2 more answers

. Find the inverse of the function below on the given interval and write it in the form yequalsf Superscript negative 1 Baseline

Elena L [17]

Answer:

The inverse of the function is $f^{-1}(x)=\frac{x-5}{3}$ .

Step-by-step explanation:

The function provided is:

$f (x)=3x+5$

Let $f(x)=y$ .

Then the value of x is:

$y=3x+5\\\\3x=y-5\\\\x=\frac{y-5}{3}$

For the inverse of the function, $x\rightarrow y$ .

⇒ $f^{-1}(x)=\frac{x-5}{3}$

Compute the value of $f[f^{-1}(x)]$ as follows:

$f[f^{-1}(x)]=f[\frac{x-5}{3}]$

$=3[\frac{x-5}{3}]+5\\\\=x-5+5\\\\=x$

Hence proved that $f[f^{-1}(x)]=x$ .

Compute the value of $f^{-1}[f(x)]$ as follows:

$f^{-1}[f(x)]=f^{-1}[3x+5]$

$=\frac{(3x+5)-5}{3}\\\\=\frac{3x+5-5}{3}\\\\=x$

Hence proved that $f^{-1}[f(x)]=x$ .

8 0

2 years ago