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2 years ago

10

This table shows the results of a survey that asked a group of people what time of day their favorite TV show aired. What time c

orresponds to the mode of this set of data? A. 8:00 P.M. B. 9:00 P.M. C. 10:00 P.M. D. 11:00 P.M.

1 answer:

irina1246 [14]2 years ago

6 0

Based on the table (see attachment), the time which corresponds to the mode of this data set is: B. 9:00 P.M.

<h3>What is mode?</h3>

A mode simply refers to a statistical term that is used to denote the value that appears most often or occurs repeatedly in a given data set.

This ultimately implies that, a mode represents the value (number) with the highest frequency and this is 9:00 P.M with a frequency of 25.

Read more on mode here: brainly.com/question/542771

#SPJ1

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What is the solution set of the following equation?

Anna007 [38]

Im pretty sure x = -0.3

8 0

3 years ago

According to the empirical (69-95-99.7) rule, if a random variable z has a standard normal distribution, then approximately 95%

Dmitry_Shevchenko [17]

Using z-scores, it is found that the value of z is z = 1.96.

-----------------------------

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula, which for a measure X, in a distribution with mean $\mu$ and standard deviation $\sigma$ , is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
Each z-score has an associated p-value, which is the percentile.

The normal distribution is symmetric, which means that the middle 95% is between the <u>2.5th percentile and the 97.5th percentile</u>.
The 2.5th percentile is Z with a p-value of 0.025, thus Z = -1.96.
The 97.5th percentile is Z with a p-value of 0.975, thus Z = 1.96.
Thus, the value of Z is 1.96.

A similar problem is given at brainly.com/question/16965597

7 0

2 years ago

Can someone explain this to me?

Deffense [45]

Answer:

200

Step-by-step explanation:

So its basically you multiply the length by the width which is 15 times 5 which is 75 then you multiply 75 times 4 which is 200 so the answer is 200.

6 0

2 years ago

Read 2 more answers

Binomial Expansion/Pascal's triangle. Please help with all of number 5.

Mandarinka [93]

$\begin{matrix}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\end{bmatrix}$

The rows add up to $1,2,4,8,16$ , respectively. (Notice they're all powers of 2)

The sum of the numbers in row $n$ is $2^{n-1}$ .

The last problem can be solved with the binomial theorem, but I'll assume you don't take that for granted. You can prove this claim by induction. When $n=1$ ,

$(1+x)^1=1+x=\dbinom10+\dbinom11x$

so the base case holds. Assume the claim holds for $n=k$ , so that

$(1+x)^k=\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k$

Use this to show that it holds for $n=k+1$ .

$(1+x)^{k+1}=(1+x)(1+x)^k$
$(1+x)^{k+1}=(1+x)\left(\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k\right)$
$(1+x)^{k+1}=1+\left(\dbinom k0+\dbinom k1\right)x+\left(\dbinom k1+\dbinom k2\right)x^2+\cdots+\left(\dbinom k{k-2}+\dbinom k{k-1}\right)x^{k-1}+\left(\dbinom k{k-1}+\dbinom kk\right)x^k+x^{k+1}$

Notice that

$\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!}{\ell!(k-\ell)!}+\dfrac{k!}{(\ell+1)!(k-\ell-1)!}$
$\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)}{(\ell+1)!(k-\ell)!}+\dfrac{k!(k-\ell)}{(\ell+1)!(k-\ell)!}$
$\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)+k!(k-\ell)}{(\ell+1)!(k-\ell)!}$
$\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(k+1)}{(\ell+1)!(k-\ell)!}$
$\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{(k+1)!}{(\ell+1)!((k+1)-(\ell+1))!}$
$\dbinom k\ell+\dbinom k{\ell+1}=\dbinom{k+1}{\ell+1}$

So you can write the expansion for $n=k+1$ as

$(1+x)^{k+1}=1+\dbinom{k+1}1x+\dbinom{k+1}2x^2+\cdots+\dbinom{k+1}{k-1}x^{k-1}+\dbinom{k+1}kx^k+x^{k+1}$

and since $\dbinom{k+1}0=\dbinom{k+1}{k+1}=1$ , you have

$(1+x)^{k+1}=\dbinom{k+1}0+\dbinom{k+1}1x+\cdots+\dbinom{k+1}kx^k+\dbinom{k+1}{k+1}x^{k+1}$

and so the claim holds for $n=k+1$ , thus proving the claim overall that

$(1+x)^n=\dbinom n0+\dbinom n1x+\cdots+\dbinom n{n-1}x^{n-1}+\dbinom nnx^n$

Setting $x=1$ gives

$(1+1)^n=\dbinom n0+\dbinom n1+\cdots+\dbinom n{n-1}+\dbinom nn=2^n$

which agrees with the result obtained for part (c).

4 0

3 years ago

Sally finds a coin with a radius of 1.5 centimeters and a thickness of 0.25 cm. It has a measured mass of 18.54 grams. How can S

mote1985 [20]

Answer:

Silver

Step-by-step explanation:

Find the volume of the coin

<u>Volume of a cylinder</u>

$\textsf{V}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}$

Given:

r = 1.5 cm
h = 0.25 cm

Substituting given values into the formula to find the volume:

$\sf \implies V=\pi (1.5)^2(0.25)$

$\sf \implies V=0.5625 \pi \:cm^3$

Find the density of the coin given it has a measured mass of 18.54 g

<u>Density formula</u>

$\sf \rho=\dfrac{m}{V}$

where:

$\rho$ = density
m = mass
V = volume

Given:

m = 18.54 g
$\sf V=0.5625 \pi \:cm^3$

Substituting given values into the density formula:

$\implies \sf \rho=\dfrac{18.54}{0.5625 \pi}$

$\implies \sf \rho=10.49149385\:g\:cm^{-3}$

Given:

$\textsf{Density of Lead}=\sf 11.3\:g\:cm^{-3}$

$\textsf{Density of Silver}=\sf 10.49\:g\:cm^{-3}$

Therefore, as $\sf \rho=10.49\:g\:cm^{-3}$ the coin is made from silver.

4 0

2 years ago