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ad-work [718]
2 years ago
10

This table shows the results of a survey that asked a group of people what time of day their favorite TV show aired. What time c

orresponds to the mode of this set of data? A. 8:00 P.M. B. 9:00 P.M. C. 10:00 P.M. D. 11:00 P.M.
Mathematics
1 answer:
irina1246 [14]2 years ago
6 0

Based on the table (see attachment), the time which corresponds to the mode of this data set is: B. 9:00 P.M.

<h3>What is mode?</h3>

A mode simply refers to a statistical term that is used to denote the value that appears most often or occurs repeatedly in a given data set.

This ultimately implies that, a mode represents the value (number) with the highest frequency and this is 9:00 P.M with a frequency of 25.

Read more on mode here: brainly.com/question/542771

#SPJ1

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What is the solution set of the following equation?
Anna007 [38]
Im pretty sure x = -0.3

8 0
3 years ago
According to the empirical (69-95-99.7) rule, if a random variable z has a standard normal distribution, then approximately 95%
Dmitry_Shevchenko [17]

Using z-scores, it is found that the value of z is z = 1.96.

-----------------------------

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula, which for a measure X, in a distribution with mean \mu and standard deviation \sigma, is given by:  

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • Each z-score has an associated p-value, which is the percentile.

  • The normal distribution is symmetric, which means that the middle 95% is between the <u>2.5th percentile and the 97.5th percentile</u>.
  • The 2.5th percentile is Z with a p-value of 0.025, thus Z = -1.96.
  • The 97.5th percentile is Z with a p-value of 0.975, thus Z = 1.96.
  • Thus, the value of Z is 1.96.

A similar problem is given at brainly.com/question/16965597

7 0
2 years ago
Can someone explain this to me?
Deffense [45]

Answer:

200

Step-by-step explanation:

So its basically you multiply the length by the width which is 15 times 5 which is 75 then you multiply 75 times 4 which is 200 so the answer is 200.

6 0
2 years ago
Read 2 more answers
Binomial Expansion/Pascal's triangle. Please help with all of number 5.
Mandarinka [93]
\begin{matrix}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\end{bmatrix}

The rows add up to 1,2,4,8,16, respectively. (Notice they're all powers of 2)

The sum of the numbers in row n is 2^{n-1}.

The last problem can be solved with the binomial theorem, but I'll assume you don't take that for granted. You can prove this claim by induction. When n=1,

(1+x)^1=1+x=\dbinom10+\dbinom11x

so the base case holds. Assume the claim holds for n=k, so that

(1+x)^k=\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k

Use this to show that it holds for n=k+1.

(1+x)^{k+1}=(1+x)(1+x)^k
(1+x)^{k+1}=(1+x)\left(\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k\right)
(1+x)^{k+1}=1+\left(\dbinom k0+\dbinom k1\right)x+\left(\dbinom k1+\dbinom k2\right)x^2+\cdots+\left(\dbinom k{k-2}+\dbinom k{k-1}\right)x^{k-1}+\left(\dbinom k{k-1}+\dbinom kk\right)x^k+x^{k+1}

Notice that

\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!}{\ell!(k-\ell)!}+\dfrac{k!}{(\ell+1)!(k-\ell-1)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)}{(\ell+1)!(k-\ell)!}+\dfrac{k!(k-\ell)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)+k!(k-\ell)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(k+1)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{(k+1)!}{(\ell+1)!((k+1)-(\ell+1))!}
\dbinom k\ell+\dbinom k{\ell+1}=\dbinom{k+1}{\ell+1}

So you can write the expansion for n=k+1 as

(1+x)^{k+1}=1+\dbinom{k+1}1x+\dbinom{k+1}2x^2+\cdots+\dbinom{k+1}{k-1}x^{k-1}+\dbinom{k+1}kx^k+x^{k+1}

and since \dbinom{k+1}0=\dbinom{k+1}{k+1}=1, you have

(1+x)^{k+1}=\dbinom{k+1}0+\dbinom{k+1}1x+\cdots+\dbinom{k+1}kx^k+\dbinom{k+1}{k+1}x^{k+1}

and so the claim holds for n=k+1, thus proving the claim overall that

(1+x)^n=\dbinom n0+\dbinom n1x+\cdots+\dbinom n{n-1}x^{n-1}+\dbinom nnx^n

Setting x=1 gives

(1+1)^n=\dbinom n0+\dbinom n1+\cdots+\dbinom n{n-1}+\dbinom nn=2^n

which agrees with the result obtained for part (c).
4 0
3 years ago
Sally finds a coin with a radius of 1.5 centimeters and a thickness of 0.25 cm. It has a measured mass of 18.54 grams. How can S
mote1985 [20]

Answer:

Silver

Step-by-step explanation:

Find the volume of the coin

<u>Volume of a cylinder</u>

\textsf{V}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

Given:

  • r = 1.5 cm
  • h = 0.25 cm

Substituting given values into the formula to find the volume:

\sf \implies V=\pi (1.5)^2(0.25)

\sf \implies V=0.5625 \pi \:cm^3

Find the density of the coin given it has a measured mass of 18.54 g

<u>Density formula</u>

\sf \rho=\dfrac{m}{V}

where:

  • \rho = density
  • m = mass
  • V = volume

Given:

  • m = 18.54 g
  • \sf V=0.5625 \pi \:cm^3

Substituting given values into the density formula:

\implies \sf \rho=\dfrac{18.54}{0.5625 \pi}

\implies \sf \rho=10.49149385\:g\:cm^{-3}

Given:

  • \textsf{Density of Lead}=\sf 11.3\:g\:cm^{-3}
  • \textsf{Density of Silver}=\sf 10.49\:g\:cm^{-3}

Therefore, as \sf \rho=10.49\:g\:cm^{-3} the coin is made from silver.

4 0
2 years ago
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