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sergey [27]
3 years ago
15

PLEASE HELP!!!

Mathematics
2 answers:
kifflom [539]3 years ago
6 0

Answer:

Option A.

Step-by-step explanation:

Given: QRST is a parallelogram and M is the intersection of diagonals.

We know that opposite sides of a parallelogram are parallel and equal.

In △QMR and △SMT,

\angle MQR=\angle MST    (Alternate interior angles)

QR=ST        (Definition of parallelogram)

\angle QRM=\angle STM    (Alternate interior angles)

Two corresponding angles and included sides are congruent.

\triangle QMR=\triangle SMT        (ASA postulate)

Hence, the correct option is A.

andreev551 [17]3 years ago
5 0

Answer:

B △QMR≅△TMS by ASA

Step-by-step explanation: Could be wrong idk.

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Please help it would be very appreciated!!
Leto [7]

Answer:

answer is 24.56cm

perimeter of half/semi circle =  \pi r + 2r

<em>one semi circle semi circles perimeter:  </em>\pi<em>*2+2*2 =10.283cm, </em>

<em>for two semi circles= 2*10.283 =20.566cm</em>

without the line below for two semi circle: 20.566-4-4=12.566 cm

both da side of rectangle is 6cm+6cm=12cm

now add the 12.566+12=24.56cm

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kondor19780726 [428]
<h3 /><h3>verified \: answer  \sqrt}</h3>

Equation for Perimeter of a rectangle: Perimeter = 2W + 2L

<h3>Defining the variables, let</h3>

<h3>Width = x</h3><h3>Length = 2x+3 (3 more than twice the width)</h3>

<h3>Plugging everything into the equation</h3>

<h3>30= 2(x) + 2(2x+3) using the distributive property,</h3>

<h3>30=2x+4x+6 combining like terms</h3>

<h3>30=6x+6 subtracting 6 from both sides,</h3>

<h3>24=6x divide both sides by 6</h3>

<h3>4=x This means that the width is 4 m.</h3>

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3 years ago
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Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

3 0
3 years ago
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