Answer:
answer is 24.56cm
perimeter of half/semi circle =
r + 2r
<em>one semi circle semi circles perimeter: </em>
<em>*2+2*2 =10.283cm, </em>
<em>for two semi circles= 2*10.283 =20.566cm</em>
without the line below for two semi circle: 20.566-4-4=12.566 cm
both da side of rectangle is 6cm+6cm=12cm
now add the 12.566+12=24.56cm
The anser is all of the above please make brainlyleist
The answer to your question should be 6.19
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Equation for Perimeter of a rectangle: Perimeter = 2W + 2L
<h3>Defining the variables, let</h3>
<h3>Width = x</h3><h3>Length = 2x+3 (3 more than twice the width)</h3>
<h3>Plugging everything into the equation</h3>
<h3>30= 2(x) + 2(2x+3) using the distributive property,</h3>
<h3>30=2x+4x+6 combining like terms</h3>
<h3>30=6x+6 subtracting 6 from both sides,</h3>
<h3>24=6x divide both sides by 6</h3>
<h3>4=x This means that the width is 4 m.</h3>
<h3>To get the length, use the expression L=2x+3 and plug in x = 4 that was already solved for</h3>
<h3>L=2(4)+3</h3>
<h3>L=8+3 = 11 m</h3>
<h3>So the dimensions of the rectangle are width is 4 m and length is 11 m.</h3>
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.