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I got the answer of 6127.731 hope this works out for you.
Answer:
c(x)=(x+3)^2+5
Step-by-step explanation:
To complete the square, the same value needs to be added to both sides.
So, to complete the square x^2+6x+9=(x+3)^2 add 9 to the expression
C(x) =x^2 +6x + 9 + 14
Since 9 was added to the right-hand side also add 9 to the left-hand side
C(x) +9= x^2 +6x + 9 + 14
Using a^2 + 2ab + b^2=(a+b)^2, factor the expression
C(x)+9= (x+3)^2 +14
Move constant to the right-hand side and change its sign
C(x)=(x+3)^2 +14 - 9
Subtract the numbers
C(x)= (x+3)^2 +5
First thing you should do is reduce coefficients.
1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6
2nd equation has multiples of 5. Divide by 5.
---> x - y = 2
Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.
x + 3y = -6
-(x - y = 2)
----------------------
4y = -8
Solve for 'y'
4y = -8
y = (-8)/4 = -2
Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0
Solution to system is:
x=0, y =-2
Answer:
y=2/3x+8
Step-by-step explanation:
