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Rzqust [24]
3 years ago
6

Solve for x. -6x = -18

Mathematics
2 answers:
Marina CMI [18]3 years ago
7 0

Answer:

x= 3

Step-by-step explanation:

-6x=-18

-18/-6= 3

x= 3

marta [7]3 years ago
3 0

Answer:

3

Step-by-step explanation:

The goal is to get the x to be on one side of the equation on its own.

-6x = -18

To get rid of the -6, we would have to do the opposite of what it's doing in the equation - in this case, we would divide, as it's the opposite of multiplying.

What we do to one side of the equation, we have to do to the other.

-6x/-6 = x

-18/-6 = 3

x = 3

Hope that makes sense!

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Please put these from greatest to least.
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Answer:

Answer is below

Step-by-step explanation:

Idk if it 430 or 436 but if it is 436.051 that goes first

then 435.786

435.100

if it is 430.051 then it is in the order of

435.781

435.100

430.051

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As said before, 160 is the correct answer
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You withdraw $29.79 from your bank account. Now your balance is −$20.51. Write and solve an equation to fi nd the amount of mone
Lunna [17]
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Find the length of the major arc in RED. Round your answers to the nearest tenth.
scoray [572]

Answer:

52.4

Step-by-step explanation:

Arc length = 2πr(θ/360)

r = 10

θ = 300°

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4 0
2 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

5 0
3 years ago
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