Part A
The small red arcs indicate that angles PQS and RQS are congruent.
13x - 1 = 2(6x + 4)
13x - 1 = 12x + 8
x = 9
m<PQR = 13x - 1 = 116
m<RQS = 6x + 4 = 6(9) + 4 = 58
m<PQS = 116 - 58 = 58
Part B
12^2 + (OH)^2 = 13^2
144 + (OH)^2 = 169
(OH)^2 = 25
OH = 5
r = OH = 5
Part C
WZ/ZY = WX/XY
24/12 = 30/XY
2 = 30/XY
2(XY) = 30
XY = 15
I think the answer would be B.
<span>log(x-3)+log(x) = 2 + log(x+2)
---------------------------
log[(x-3)x] - log(x+2) = 2
-----
log[(x^2-3x)/(x+2)] = 2
----
(x^2-3x)/(x+2) = 2^2
-------
x^2-3x = 4x+8
x^2 - 7x - 8 = 0
Factor:
(x-8)(x+1) = 0
Positive solution:
x = 8</span>
Answer:
h=8
Step-by-step explanation:
a²+b²=c²
a=A
b=12
c=13
therefore substitute
A²+(12)²=(13)²
A²=13²-12²
A²=25
A=5
h=3+A
h=3+5
h=8
<span><span>Volume (V) = <span><span>Volume (V) = <span>3 * √3 * l² * h</span></span>2</span></span></span>
l=4
h=9
V<span><span>= (<span>3 * √3 * 4² * 9)/</span></span>2 = 374.12297 round off as needed</span>
