The parametric equations for x and y describe a circle of radius 10 m, so the length of the base of the fence is the length of the circumference of a circle of radius 10 m. The formula for that circumference (C) is ...
... C = 2πr
... C = 2π·(10 m) = 20π m
The height as a function of angle (t) is found by substituting for x and y.
... h(t) = h(x(t), y(t)) = 4 + 0.01·((10cos(t))²-)10sin(t))²) = 4+cos(2t)
The average value of this over the range 0 ≤ t ≤ 2π is 4, since the cosine function has two full cycles in that range, and its average value over a cycle is zero.
Thus, the area of one side of the fence is that of a rectangle 20π m long and 4 m wide. That will be
... (20π m)·(4 m) = 80π m²
The amount of paint required to cover both sides of the fence is
... 2×(80π m²)×(1 L)/(10 m²) = 16π L ≈ 50.3 L
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You can work out the integral for area as a function of t. When you do, you will find it gives this same result.
Answer:
Last Option moved 
units right
Step-by-step explanation:
If we have a function f(x) and we want to move it horizontally then we make the transformation:
If 
then the graph of f(x) moves horizontally h units to the right
If 
then the graph of f(x) moves horizontally h units to the left.
In this case we have the function 
and the transformation is performed to obtain 
Notice that in this transformation
<u><em>Then the graph of moves horizontally to the right</em></u>
We know that
cos²(theta)=0.21
sin²(theta)+cos²<span>(theta)=1
</span>sin²(theta)=1-cos²(theta)------> sin²(theta)=1-(0.21)-----> 0.79
sin(theta)=√0.79
sin(theta)=0.89
the answer is
the value of sin(theta) is 0.89
That would be zero.
Obtuse means more than 90 degrees. A triangle's angles add up to 180 degrees so can't have two obtuse angles.
