Answer:
38.77 yd³
Step-by-step explanation:
The volume of the sphere can be determined by using the formula 4πr³/3.
[Where "r" is the radius of the circle].
<u>We are given that:</u>
Radius of circle = 2.1 yd
<u />
<u>When we substitute the radius in the formula, we get;</u>
⇒ 4 × π × (2.1)³/3
<u>Let π be substituted as 3.14. Then;</u>
⇒ 4 × π × (2.1)³/3
⇒ 4 × (3.14) × (2.1)³/3
<u>When evaulating the cube of 2.1, we get;</u>
⇒ 4 × (3.14) × (2.1)³/3
⇒ 4 × (3.14) × (2.1) × (2.1) × (2.1)/3
<u>When simplified, we get;</u>
⇒ 4 × (3.14) × (2.1) × (2.1) × (2.1)/3
⇒ 4 × (3.14) × (2.1) × (2.1) × (0.7)
⇒ 4 × (3.14) × (4.41) × (0.7)
⇒ (12.56) × (4.41) × (0.7)
⇒ 38.77272 ≈ 38.77 yd³ (Rounded to nearest hundredth)
Therefore, the volume of the sphere is 38.77 yd³.
Answer:
accounting function
Step-by-step explanation:
Answer:
ones
Step-by-step explanation:
Step-by-step explanation:
The formula to find the final velocity, v of an object having an initial velocity , u , and acceleration , a , at time t is v=u+at
(a) v=u+at
Subtract u from both sides,
v-u=u+at-u
v-u=at
Dividing both sides by t.
![a=\dfrac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv-u%7D%7Bt%7D)
(b) The relationship between the acceleration and time for a given initial and final velocity is given by "
![s=ut+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
Where
s is the distance covered
t is the time
Hence, this is the required solution.