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Snowcat [4.5K]
3 years ago
7

I'm pretty sure they're congruent according to the sas postulate but could someone make sure?? thx <3

Mathematics
2 answers:
son4ous [18]3 years ago
7 0

Answer:

The triangles aren't necessarily congruent. SAS postulate is side angle side, which means that the angle that is congruent must be between the two sides that are congruent. DF is congruent to MN, and DG is congruent to MP. This means, that angle D must be congruent to angle M.

However, we only know that D is congruent to P, not M.

These triangles are not necessarily congruent.

daser333 [38]3 years ago
4 0

[ This answer is not viewable due to inaccuracy. ]

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How can you get 24 by using 1, 1/2, 3 and 6 (one each) with simple mathematical operations?
Tcecarenko [31]

Answer:

(3+1)X 6

Step-by-step explanation:

that means 4x6

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(V. An aeroplane is flying parallel to the Earth's surface at a speed of 175 m/sec and at a height of 600 m. The angle of elevat
GREYUIT [131]

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3 years ago
The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar
Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, H_0 : \mu \leq  3.5%

    ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, H_0 : \mu \leq  3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

                T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where,  \bar X = sample mean debt ratio of Ohio banks = 6%

             s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 1.83%

             n = sample of banks = 7

So, test statistics = \frac{6-3.5}{\frac{1.83}{\sqrt{7} } }  ~ t_6

                             = 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

7 0
3 years ago
jane is twice as old as Barbara. Michael is 7 years older than Jane. If Michael is 21, which equation could be used to find Barb
dedylja [7]

Step-by-step explanation:

J = 2b

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J = 21 - 7

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<em>Equation:</em>

If M is J+7, so then J = 21-7. J is 2*b, so 2*b = 21-7. Then you subtract and divide.

3 0
2 years ago
A population is known to be normally distributed with a standard deviation of 2.8. (a) Compute the 95% confidence interval on th
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Answer:

Step-by-step explanation:

Mean = sum of terms/number of terms

The mean of the given sample is

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We will apply the formula

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= mean ± z ×standard deviation/√n

Where

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It becomes

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= 14.2 ± 1.96 × 0.933

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The upper end of the confidence interval is 16.03

b)

For a confidence level of 99%, the corresponding z value is 2.58

We will apply the formula

Confidence interval

= mean ± z ×standard deviation/√n

Where

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14.2 ± 2.58 × 2.8/√9

= 14.2 ± 2.58 × 0.933

= 14.2 ± 2.4

The lower end of the confidence interval is 11.8

The upper end of the confidence interval is 16.6

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