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2 years ago

Multiply and express your answers in mixed numbers 1/3 x 5

Mathematics

1 answer:

schepotkina [342]2 years ago

7 0

$\frac{1}{3} \times \frac{5}{1} = \frac{5}{3}$

^Here's the answer. Any number will have a denominator of 1. Then, multiply as usual and you'll get the answer.

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Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0

gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

$ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0$

Divide this by t to get in linear form

$y'+6y/t = t-1+1/t$

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/t $e^(\int 1/tdt) = t$

So solution would be

$yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C$

siubstitute y(1) = 16

$16 = 16^3/3-128+1+C\\C = -1206$

4 0

3 years ago

Por favor denme una ecuación a esta pregunta:

Katena32 [7]

Answer:

x + 13 = 25

Step-by-step explanation:

Se puede representar "un número" con x.

"Adiciona" significa +.

x + 13

"El resultado" significa =.

x + 13 = 25

7 0

2 years ago

Question 8 of 25<br> Which of the following is the quotient of the rational expressions shown here?

Alla [95]

Answer:

B. (5x+5)/(x²-2x)

Step-by-step explanation:

As with numerical fractions, division by a rational expression is equivalent to multiplication by its reciprocal.

<h3>As a multiplication problem</h3>

$\dfrac{5}{x-2}\div\dfrac{x}{x+1}=\dfrac{5}{x-2}\times\dfrac{x+1}{x}$

<h3>Product of rational expressions</h3>

As with numerical fractions, the product is the product of numerators, divided by the product of denominators.

$=\dfrac{5(x+1)}{x(x-2)}=\boxed{\dfrac{5x+5}{x^2-2x}}$

4 0

1 year ago

Find the slope and y-intercept of the line

Serhud [2]

Answer:

Step-by-step explanation:

The slope is 1. Note how each time x increases by 1 unit, y also increases by 1 unit.

The y-intercept is (0, -1).

Answer C is correct.

5 0

2 years ago

Assume the annual day care cost per child is normally distributed with a mean of $9000 and a standard deviation of $1000. What

Tpy6a [65]

Answer:

65.54% (nearest hundredth)

Step-by-step explanation:

Given:

$\sf \mu=9000$

$\sf \sigma=1000$

$\sf X \sim N(\mu, \sigma^2)\implies X \sim N(9000,1000^2)$

P(X > 8600) = 1 - P(X ≤ 8600)

= 1 - 0.3445782584

= 0.6554217416

= 65.54%

3 0

1 year ago