All categories

3 years ago

What is the expression in radical form? (7x3y2)2/7

Mathematics

1 answer:

zvonat [6]3 years ago

6 0

The answer would be 35

You might be interested in

Math problems solve

Stolb23 [73]

Number???what do you want?

6 0

3 years ago

(4x-5)^3 - (x^2 + 4x+1)(4x-3)=?

neonofarm [45]

Answer:

64x^3-241x^2+296x-125

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Help me to solve problem pless

sergejj [24]

Answer:

5 x -3 +6

= 5 x 6 + -3

= 30 + -3

= 27

8 0

3 years ago

Read 2 more answers

Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.

marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}$

$\dfrac{a^m}{a^n} = a^{(m-n)}$

$\sqrt[m]{a^n} = a^{\frac{n}{m}}$

$(a^m)^n = a^{m\times n}$

$(m\times n)^a = m^a\times n^a$

The expression can be written as $x^9\sqrt[3]{y}$ .

Given to us

$(x^{27}y)^\frac{1}{3}$

$(x^{27}y)^\frac{1}{3}$

Using the exponential property $(m\times n)^a = m^a\times n^a$ ,

$=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}$

Hence, the expression can be written as $x^9\sqrt[3]{y}$ .

Learn more about Exponent properties:

brainly.com/question/1807508

5 0

2 years ago

Read 2 more answers

In 5 seconds an athlete runs 40 feet. what is the average speed in miles per hour?

NikAS [45]

Answer:

12 x 40 = 480 feet per minute.

480 x 60 = 28800 feet per hour.

28800/5280 = 5.45 miles per hour.

Hope that helps.Thank you!!!

6 0

3 years ago

Read 2 more answers