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dalvyx [7]
3 years ago
13

A’s DJ service charges a $200 setup fee and $75 an hour after that.

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

The total cost includes the setup cost + per hour cost.

Let, x represents the time and y represents the total cost.

y=200+75x .... (1)

Let Y represent the cost for B's DJ service.

y=125x .... (2)

a. Graphing both the equations give the intersection point (solution) as (4,500)

It means for 4 hours, the total cost of both the DJ's is same at $500.

b. Substitution Method.

Plug y = 125x in equation (1)

125x= 200+75x

125x-75x=200

50x=200

x=4

y=125\times 4 =500

Hence, the total cost for 4 hours in both the service is $500.

c. Addition method.

Multiply equation (2) by -1

-y = -125x.... Equation (3).

Add euation (1) and equation (3)

y+(-y) = 200+75x-125x

0=200-50x

50x=200, x=4

y=500

Solution: For x = 4, y = 500 ( same as the previous two methods)

For x = 2, equation (1)

y=200+(75\times 2) = 350

For x = 2, equation (2)

y= 125\times 2 =250

Hence, for 2 hours, DJ B would be a better choice since it would charge $250.

For x = 6 hours, equation (1)

y=200+(75\times 6) =650

For x= 6, equation (2)

y=125\times 6=750

For 6 hours, DJ A would be  better option since it charges $650 for 6 hours.



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