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Alexandra [31]
3 years ago
6

Find the area of a rectangle 3yds by 4/7yds

Mathematics
1 answer:
jasenka [17]3 years ago
5 0

\text{We're trying to find the area of the rectangle}\\\\\text{We know the dimensions are 3 by 4/7}\\\\\text{The formula to find the area of a rectangle is length x width}\\\\\text{Solve for area:}\\\\3\cdot\frac{4}{7}\\\\\text{Multiply the 3 to the numerator}\\\\\frac{12}{7}\\\\\text{Since we can't simply it, we'll leave it as is}\\\\\boxed{\text{Answer:} \frac{12}{7}\,\,yd^2}

You might be interested in
If f(x) = 4x2 and g(x) = x+1, find (f.g)(x).​
joja [24]

Answer:

8x+8

Step-by-step explanation:

(f.g)(x)= (f)(g)

(f.g)(x)=(4.2)(x+1)

(f.g)(x)=(8)(x+1)

(f.g)(x) =8x+8

7 0
3 years ago
the sum of all but one interior angle of a heptagon is 776°. what is the measure of the final interior angle?
soldi70 [24.7K]

Answer:

The final interior angle = 124°

Step-by-step explanation:

A heptagon has 7 sides. The sum of the interior angles formula:

The sum of the interior angles =  (n - 2)180 where n = number of sides.

The sum of the interior angles= (7 - 2)180° = 900°

Six interior angles = 776°.

The final interior angle + six interior angle = 900°

The final interior angle + 776° = 900°      

The final interior angle = 900° - 776°

The final interior angle = 124°

6 0
2 years ago
A container holds 50 electronic components, of which 10 are defective.
Gala2k [10]

Answer:

There is some inforrmation that is missing in this question. It should read:

A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .

Answers

Part 1.   0.02

Part 2.  0.0375

Explanation

The probability is a chance of an event happening. It is calculated as;

probability = (Number of favourable outcome)/(Number of available outcome)

Part 1

6 are chosen at random. If 4 are not defective, then 2 are defective.

P(at least 4 are not defective) = 4/40 × 2/10

                                               = 1/10 ×1/5

                                               = 1/50

                                                = 0.02

Part 2

8 are chosen at random. If 3 are defective, the 5 are not defective.  

P(3 are defective) = 3/40 × 5/10  

                            = 15/400

                            = 3/80

                           = 0.0375

Step-by-step explanation:

4 0
3 years ago
Did i do this correctly?
den301095 [7]
Yes u did do this correctly
5 0
3 years ago
Read 2 more answers
Help with 1 and 2 this is urgent
vampirchik [111]
The answer to the first part is 172 plants per row with a remainder of 3 plants
The answer to the second part is, Martin knows that 7 goes into 700 100 times, 7 goes into 490 70 times, and 7 goes into 17 twice with a remainder of 3. He then adds 100 70 and 2 together to get 172 with a remainder of 3.
3 0
3 years ago
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