Answer:
0.0100250
0.0001566
0.0000009445555
Step-by-step explanation:
Given the following :
Total number of containers = 400
Number of defective oranges = 5
2 are randomly selected without replacement :
A.) What is the probability that the second one selected is defective given that the first one was defective?
Since selection is without replacement and given that the first pick is defective ; number of defective oranges left = 4 ; total oranges left in container = (400 - 1) = 399
Hence,
Probability = (required outcome / Total possible outcomes)
P(2nd defective given 1st is defective) = 4 / 399
27. What is the probability that both are acceptable?
This means probability that both picks aren't defective.
Ist pick = 1 - P(defective) = (1 - (395/400) = 0.0125
2nd pick = 1 - P(defective) 1 - (394/399) = 0.0125313
.Hence, 0.0125 × 0.0125313 = 0.0001566
28. If three are selected without replacement, what is the probability that all three are defective?
1st pick = 5 / 400 = 0.0125
2nd pick = 4 / 399 = 0.0100250
3rd pick = 3 / 398 = 0.0075376
Hence, (0.0125 × 0.0100250 × 0.0075376) = 0.0000009445555
