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4 years ago

Write a balanced equation for the single-displacement reaction of Al(s) with CuSO4(aq). Include states of matter in your answer.

Chemistry

1 answer:

Alex Ar [27]4 years ago

8 0

Answer:

2 Al(s) + 3 CuSO₄(aq) ⇒ 3 Cu(s) + Al₂(SO₄)₃(aq)

Explanation:

Let's consider the single displacement reaction of Al(s) with CuSO₄(aq). Copper has a higher reduction potential than aluminum, so aluminum will take the place of copper to form aluminum sulfate and metallic copper. The corresponding balanced chemical equation is:

2 Al(s) + 3 CuSO₄(aq) ⇒ 3 Cu(s) + Al₂(SO₄)₃(aq)

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Part c

algol13

Distilling ocean water would be a good solution to meet this community's water needs because it will prevent some water borne diseases such as cholera, diarrhea, typhoid etc.

<h3>Importance of water distillation</h3>

Water Distillation Systems has several advantages and some of the advantages include;

It removes waterborne biological contaminants such as bacteria, viruses, organic and inorganic chemicals, heavy metals, etc
It makes the water fit for consumption

Thus, distilling ocean water would be a good solution to meet this community's water needs because it will prevent some water borne diseases such as cholera, diarrhea, typhoid etc.

Learn more about water distillation here: brainly.com/question/3166914

#SPJ1

6 0

2 years ago

Se sabe que 10 g de calcio reaccionan con 4 g de oxígeno para obtener 14 g de óxido de calcio. Indica la cantidad de óxido de ca

egoroff_w [7]

Answer:

Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

$2Ca+O_2\rightarrow 2CaO$

De este modo si asumimos el ejemplo dado, 50 gramos de calcio, cuya masa atómica es 40 g/mol y 50 g de oxígeno, cuya masa atómica como gas diatómico es 32 g/mol, antes de calcular los gramos de óxido de calcio producidos, debemos identificar el reactivo límite. Así, calculamos las moles de calcio disponibles en 50 g:

$mol_{Ca}^{disponible}=50gCa*\frac{1molCa}{40gCa} =1.25molCa$

Y también las moles de calcio consumidas por los 50 g de oxígeno, utilizando su relación molar 2:1:

$mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa$

Por lo tanto, hay menos calcio disponible que el que consume el oxígeno, por lo que el calcio esel reactivo límite. Ahora, con este, calculamos los gramos de óxido de calcio, cuya masa molar es 56 g/mol, que se producen:

$m_{CaO}=1.25molCa*\frac{2molCaO}{2molCa}* \frac{56gCaO}{1molCaO}\\ \\m_{CaO}=70gCaO$

Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

4 0

3 years ago

Read 2 more answers

How many decigrams are in 4.6 decagrams?

11111nata11111 [884]

Answer:

$\large \boxed{\text{460 dg}}$

Explanation:

1. Convert decagrams to grams

$\text{Mass} = \text{4.6 dag} \times\dfrac{\text{10 g}}{\text{1 dag}} = \text{46 g}$

2. Convert grams to decigrams

\ $\text{Mass} = \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}$

3 0

3 years ago

Read 2 more answers

4 outer planets in order

Gwar [14]

Jupiter, Saturn, Uranus, Neptune, Jovian... is your answer.

8 0

3 years ago

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What is the chemical reaction of aluminum and ferric oxide to produce iron and aluminum oxide?

AnnZ [28]

Answer:

Ferric oxide reacts with aluminium to produce aluminium oxide and iron. The balanced chemical equation for the given reaction is : Fe2O3 + 2Al → Al2O3 + 2Fe.

6 0

3 years ago