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3 years ago

What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?

1 answer:

3 0

Answer is: volume of H₂SO₄ is 42.1 mL.
Chemical reaction: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.
c(H₂SO₄) = 0,4567 M = 0,4567 mol/L.
V(NaOH) = 30 mL ÷ 1000 mL/L = 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H₂SO₄) : n(NaOH) = 1 : 2.
n(H₂SO₄) = 0,01926 mol.
V(H₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).
V(H₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.
V(H₂SO₄) = 0,0421 L = 42,1 mL.

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Answer:

5.52 g

Explanation:

4NH₃ + 5O₂ → 4NO + 6H₂O

First we convert the given masses of both reactants into moles, using their respective molar masses:

6.30 g NH₃ ÷ 17 g/mol = 0.370 mol NH₃

1.80 g O₂ ÷ 32 g/mol = 0.056 mol O₂

Now we calculate with how many NH₃ moles would 0.056 O₂ moles react, using the stoichiometric coefficients:

0.056 mol O₂ * $\frac{4molNH_3}{5molO_2}$ = 0.045 mol NH₃

As there more NH₃ moles than required, NH₃ is the excess reactant.

Then we calculate how many NH₃ moles remained without reacting:

0.370 mol NH₃ - 0.045 mol NH₃ = 0.325 mol NH₃

Finally we convert NH₃ moles into grams:

0.325 mol NH₃ * 17 g/mol = 5.52 g

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3 years ago

The shape of a molecule is tetrahedral. How many lone pairs are most likely on the central atom?

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2 years ago

How many total electrons does the P^3- ion have? O a. 3 O b. 31 O c.1 O d. 15 O e. 18

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Answer:

e. 18

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