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3 years ago

15

Write a balanced equation for the combustion of hexane, C6H14 (l)

1 answer:

stich3 [128]3 years ago

8 0

The combustion of hexane (C6H14), a component of gasoline, is represented by the balanced chemical equation: 2 C6H14(l) + 19 O2(g) " 12 CO2(g) + 14 H2O(g). If 1.0 mole of hexane undergoescombustion, moles of O2 are required.

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Why boron trifluoride is nonpolar and sulphur dioxide is polar

ella [17]

it small because that bond is not very polar notice that all of those arrows they cancel. because they point in opposite directions. that's why BH 3 is nonpolar if we were to draw the Lewis structure of bf3. ... so even though the boron fluorine bond is polar the molecule as a whole is nonpolar.

6 0

3 years ago

4.00 g of O2 gas are in a sealed, 2.00 L gas canister at 22.0 °C what is the pressure inside this container (in atm)?

Volgvan

Answer:

1.51448 atms

Explanation:

6 0

3 years ago

Q05 the "atomic number" of an atom is determined by the number of ________ it has.

Alexxx [7]

The atomic number of an atom is determined by the number of protons it has..

It is also the whole number shown on the periodic table

6 0

4 years ago

What is the wavelength (in nm) of

LenKa [72]

Answer:

λ = 0.45×10⁻⁶ m

Explanation:

Given data:

Wavelength of blue light = ?

Frequency of blue light = 6.69×10¹⁴ s⁻¹

Solution:

Formula;

Speed of wave = wavelength × frequency

Speed of wave = 3.00×10⁸ m/s

by putting vales,

3.00×10⁸ m/s = λ × 6.69×10¹⁴ s⁻¹

λ = 3.00×10⁸ m/s / 6.69×10¹⁴ s⁻¹

λ = 0.45×10⁻⁶ m

6 0

3 years ago

g A microwave oven heats by radiating food with microwave radiation, which is absorbed by the food and converted to heat. If the

Sliva [168]

Answer:

The total photons required = 5.19 × 10²⁸ photons

Explanation:

Given that:

the radiation wavelength λ= 12.5 cm = 0.125 m

Volume of the container = 0.250 L = 250 mL

The density of water = 1 g/mL

Density = mass /volume

Mass = Volume × Density

Thus; the mass of the water = 250 mL × 1 g/mL

the mass of the water = 250 g

the specific heat of water s = 4.18 J/g° C

the initial temperature $T_1$ = 20.0° C

the final temperature $T_2$ = 99° C

Change in temperature $\Delta T$ = (99-20)° C = 79 ° C

The heat q absorbed during the process = ms $\Delta T$

The heat q absorbed during the process = 250 g × 4.18 J/g° C × 79° C

The heat q absorbed during the process = 82555 J

The energy of a photon can be represented by the equation :

= hc/λ

where;

h = planck's constant = $6.626 \times 10^{-34} \ J.s$

c = velocity of light = $3.0 \times 10^8 \ m/s$

= $\dfrac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{0.125}$

= $1.59024 \times 10^{-24}$ J

The total photons required = Total heat energy/ Energy of a photon

The total photons required = $\dfrac{82555 J}{1.59024 \times 10^{-24}J}$

The total photons required = 5.19 × 10²⁸ photons

5 0

3 years ago