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ra1l [238]
3 years ago
10

Modify isoleucine, below, to show its structure at pH 1 and pH 13.

Chemistry
1 answer:
NeTakaya3 years ago
7 0
I have attached the answer

remember that when the solution is acidic, pH lower than 7. there are extra H+ that the amino acid can take. the basic part of the amino acid takes this extra hydrogen (the nitrogen).

when the pH is higher than 7, basic, there are not much H+ available. the amino acid loses a H+. the acid part of the amino acid loses the H (the carboxylic part). 

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How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm
Ierofanga [76]
Answer:

= 46.06 grams

Explanation:

P=cRT

25 = c (0.0821)(298)

concentration = c = 1.021 M

number of moles = (1.021)(0.75) = 0.7664 moles

mass = (0.7664)(60.10)=40.06 grams
3 0
3 years ago
Can somebody help me with this question please
Tasya [4]

Answer:

concave lens

Explanation:

it's concave lens because it diverges the ray/beam of light.

7 0
3 years ago
At 0 degrees Celsius, a gas occupies 22.4L. How hot must the gas be in celcius to reach a volume of 25.0L
NikAS [45]

Answer:

31.7 °C

Explanation:

Charles law states that for volume of a gas is directly proportional to the absolute temperature for a fixed amount of gas at constant pressure

we can use the following equation

V1/T1 = V2/T2

where V1 is volume and T1 is temperature at first instance

V2 is volume and T2 is temperature at second instance

temperature should be in kelvin scale

T1 - 0 °C + 273 = 273 K

substituting the values in the equation

22.4 L / 273 K = 25.0 L / T2

T2 = 304.7 K

temperature in celcius is - 304.7 K - 273 = 31.7 °C

the gas must be 31.7 °C to reach a volume of 25.0 L

7 0
3 years ago
Round to 4 significant figures.<br> 0.007062
lapo4ka [179]

Answer:

Hey there!

This is already rounded to four significant figures!

Zeroes after the decimal but before the 7 don't count, and 7, 0, 6, and 2 count as significant figures.

So, the answer would be 0.007062.

Let me know if this helps :)

8 0
3 years ago
PLZ HELP For the reaction: 2NO2(g) → N2O4(l),
Furkat [3]

Answer: \Delta H_{rxn}=-20kJ/mol-(+66kJ/mol)

Explanation:

Heat of reaction or enthalpy change is the energy released or absorbed during the course of the reaction.

It is calculated by subtracting the enthalpy of reactants from the enthalpy of products.

\Delta H=H_{products}-H_{reactants}

\Delta H = enthalpy change = ?

H_{products} = enthalpy of products

H_{reactants} = enthalpy of reactants

For the given reaction :

2NO_2(g)\rightarrow N_2O_4(l)

\Delta H=H_{N_2O_4}-2\times H_{NO_2}

\Delta H=-20kJ/mol-(+66kJ/mol)

6 0
3 years ago
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