Answer:
D
Step-by-step explanation:
Because the theoretical probability is greater than the experimental probability
(-2x2y3)(14x2y3) = -28x^4y^6
Answer:
5 a^3 c
Step-by-step explanation:
5 • a • a • c • a
There are 3 a's so it becomes a^3
5 a^3 c
Answer:
How would the function change if the base of the exponent were between 0 and 1? If the base of the exponent were 1, the function would remain constant. The graph would be a horizontal line. If the base of the exponent were less than 1, but greater than 0, the function would be decreasing.
Step-by-step explanation:
Answer:
The model for the temperature of the drink can be written as

Step-by-step explanation:
For a cold drink in a hotter room, we can say that the rate of change of temperature of the drink is proportional to the difference of temperature between the drink and the room.
We can model that in this way

If we rearrange and integrate

We know that at time 0, the temperature of the drink was 52°F. Then we have:

We also know that at t=2, T=55°F

The model for the temperature of the drink can be written as
