What is the perimeter of a quadrilateral with vertices at (3,-6),(8,-6),(3,-4), and (8,-4)
1 answer:
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Answer:
Step-by-step explanation:
(
)
Multiply by each term in the parentheses.
+
Now, all you have to do is simplify.
Pythagorean Theorem: a^2+b^2=c^2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
b = 21.2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
b = 21.2
Answer:
the given expression is equivalent to
Step-by-step explanation: