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2 years ago

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Which pairs of quadrilaterals can be shown to be congruent using

1 answer:

Zielflug [23.3K]2 years ago

3 0

Rigid transformation do not alter the sides and angle measurements of a shape.

The true statements are:

<em>quadrilateral 1 and quadrilateral 2 - Not congruent </em>
<em>quadrilateral 1 and quadrilateral 3 - Not congruent </em>
<em>quadrilateral 1 and quadrilateral 4 - Not congruent </em>
<em>quadrilateral 2 and quadrilateral 3 - Congruent </em>

<em />

From the graph, we have the following highlights

Quadrilaterals 2, 3 and 4 are congruent
Quadrilateral 1 does not have equal measure with any of the other quadrilaterals.

Hence, the first three statements are not congruent, while the last statement is congruent.

Read more about congruent shapes at:

brainly.com/question/24430586

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What is the length of the altitude of the equilateral triangle below?

balandron [24]

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3 years ago

The one i chose is wrong i think help.

const2013 [10]

Answer:

You are correct

Step-by-step explanation:

collinear means that they are on the same line, so they are collinear because of the definition of collinear

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3 years ago

230kilometer what is the speed in miles per hour

sineoko [7]

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142.92

Step-by-step explanation:

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3 years ago

A packing box measures 36 centimeters by 14 centimeters by 20 centimeters. What is the volume of the box?

natima [27]

Answer:

1000

Step-by-step explanation:

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3 years ago

Listed below are speeds (mi/h) measured from southbound traffic on I-280 near Cupertino, California (based on data from SigAlert

adell [148]

Answer:

Option (B) is the correct answer to the following question.

Step-by-step explanation:

Step-1: We have to find the Mean of the series.

The series is Given in the question 62 61 61 57 61 54 59 58 59 69 60 67.

$Mean(\overline{x})=\frac{62+61+61+57+61+54+59+58+59+69+60+67}{12}$ $= 60.67$

Step-2: We have to find the Standard Deviation.

Let Standard Deviation be x.

Formula of Standard Deviation is: $s= \sqrt{\frac{\sum(x_{i}+\overline{x})}{n-1}}$

Put value in formula of Standard Deviation,

$s= \sqrt{\frac{(62+60.67)^{2}+(61+60.67)^{2}+(61+60.67)^{2}+(57+60.67)^{2}+....(67+60.67)^{2}}{n-1}}$ = 40.75

Step-3: Then, we have to find the critical value by chi-square.

$X_{1-\alpha/2}^{2}=3.82$

$X_{1-\alpha/2}^{2}=21.92$

Then, find the confidence interval which is 95%.

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{21.92}.(4.075)^2 }\approx2.8868 \\ i.e 2.9$

$\sqrt{\frac{(n-1).s^2}{X_{\alpha/2}^{2}} } = \sqrt{\frac{12-1}{3.816}.(4.075)^2 }\approx6.9188 \\ i.e 6.9$

5 0

3 years ago