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2 years ago

Which pairs of quadrilaterals can be shown to be congruent using

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

3 0

Rigid transformation do not alter the sides and angle measurements of a shape.

The true statements are:

quadrilateral 1 and quadrilateral 2 - Not congruent
quadrilateral 1 and quadrilateral 3 - Not congruent
quadrilateral 1 and quadrilateral 4 - Not congruent
quadrilateral 2 and quadrilateral 3 - Congruent

From the graph, we have the following highlights

Quadrilaterals 2, 3 and 4 are congruent
Quadrilateral 1 does not have equal measure with any of the other quadrilaterals.

Hence, the first three statements are not congruent, while the last statement is congruent.

Read more about congruent shapes at:

brainly.com/question/24430586

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You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$

6 0

3 years ago

What is the third quartile of this data set 20,21,24,25,28,29,35,37,39,42,44

dezoksy [38]

Answer:

The third quartile would be 39.

Step-by-step explanation:

• Since the numbers are already in order, the next step would be to find the median:

- The median is the middle number; found by ordering all data points and picking out the one in the middle.

The median would be 29.

• The first quartile, is denoted as Q1 and is the middle number that falls between the smallest value of the data set and the median.

The first quartile would be 24.

• The third quartile, is denoted as Q3 and is the median of the upper half of the data set.

The third quartile would be 39.

If I helped, please mark me the Brainliest!?!

6 0

3 years ago

Help pls i dont know

Oksana_A [137]

I'm sorry the picture is blurry. Could you post another one.

7 0

3 years ago

There are 8 trailmix bags in one box. Clarissa buys 5 boxes. She gives an equal number of bags of trailmix to 4 friends. How man

JulsSmile [24]

Each friend receives 2 bags because 4 divided by 8 is 2

3 0

3 years ago

Solve algebraically. 6(t-2) + 15t < 5(5 + 3t) With work shown please!!

sammy [17]

Step-by-step explanation:

6t-12+15t | 25+15t

21t-12 | 25+15t

21t-12 < 25+15t

hence proved..

8 0

3 years ago

Read 2 more answers