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Darina [25.2K]
3 years ago
11

Help me pls lol lollll

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

hope I got this right it's been a while

Step-by-step explanation:

-15n^4t^6y^5

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(x=1)^2-4x=(x-1)^2 simplify and answer
Dennis_Churaev [7]

Step-by-step explanation:

Firstly, there's a typing error at (x=1)². I assume it is (x-1)². If my assumption is correct,then:

x²-2x+1-4x=x²-2x+1

x²-6x+1-x²+2x-1=0

-4x=0

x=0

5 0
2 years ago
Find the perimeter of the following polygon. Be sure to include the correct unit in your answer.
slava [35]

Answer:

48

Step-by-step explanation:

All you got to do is add all of them together

8 0
3 years ago
Express 18 as a fraction of 27. <br> Give your answer in its simplest form
den301095 [7]

Answer:

Thus, 2/3 is the simplified fraction for 18/27 by using the GCD or HCF method. Thus, 2/3 is the simplified fraction for 18/27 by using the prime factorization method

Step-by-step explanation:

hope l am not late!

6 0
3 years ago
Write the following number in standard decimal form.<br> one and eighty-five hundredths
sergejj [24]

Answer:

1.85

Step-by-step explanation:

0ne (1) and Eighty - five hundredths (0.85)

Hope this helps

Mark Brainliest!

7 0
2 years ago
Read 2 more answers
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
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