Question

We want to find the zeros of this polynomial:

Answer 1

Answer:

x=-3        x=-1            x=2         x=-2

Step-by-step explanation:

p(x) = (x^2 + 4x + 3)(x^2 – 4)

Set this equal to zero to find the x intercepts

0 = (x^2 + 4x + 3)(x^2 – 4)

Using the zero product property

(x^2 + 4x + 3) =0      (x^2 – 4)  =0

Factor

(x+3)(x+1) =0            (x-2) (x+2)=0

Using the zero product property

x+3 =0  x+1 =0          x-2 =0  x+2 =0

x=-3        x=-1            x=2         x=-2