Answer:
The sample space would be infinite
{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}
1/8
Step-by-step explanation:
The sample space would be infinite
{HH, TTTHH, TTTTHH, TTTTTTTHH.......................}.
This is because the number of times the coin would be flipped is not specified. So, you can keep flipping the coin forever.
If the coin is tossed four times then the sample space would be
{HHHH HTHH THHH HTHT
HHHT HTTH TTHH THTH
HHTT HHTH TTTH THHT
HTTT TTTT TTHT THTT}
HTHH and TTHH are the only two cases where two consecutive tosses will result in two heads
Probability that the coin will be tossed four times is 2/16 = 1/8
So for this trinomial, I will be factoring by grouping. Firstly, what two terms have a product of 16x^2 and a sum of 10x? That would be 8x and 2x. Replace 10x with 2x + 8x:
Next, factor x^2 + 2x and 8x + 16 separately. Make sure that they have the same quantity inside the parentheses: 
<u>Now you can rewrite this as 
, which is your final answer.</u>
If your trying to solve for x it’s 40, x=40
2 times 1/2x =2x20
x=2x20
x=40
Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
