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Snowcat [4.5K]
3 years ago
14

Say there are 20 people in a house that really want to go to a party and they can only take 12 people and everyone wants to go a

nd they just called and said that dogs can go too. And those same people get excited that the dogs can go and i have 40 dogs and not all dogs can go what do u think i should do?
Mathematics
1 answer:
frosja888 [35]3 years ago
5 0
Get some that are your favorite?
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what is the unit rate of 3 pizzas for $19.99 and round the answer to nearest hundredth ? PLZzz HELP ASAP!!!!​
kipiarov [429]

Divide 19.99 / 3

Get 6.663

Round to 6.66

Unit rate for 3 pizzas at 19.99 is 6.66

4 0
4 years ago
What is the following product?
KiRa [710]

ANSWER

2 \sqrt{42} +7  \sqrt{2}- 6- \sqrt{21}

EXPLANATION

The given product is:

( \sqrt{14}  -  \sqrt{3} )( \sqrt{12} +  \sqrt{7}  )

We expand using the distributive property to obtain:

\sqrt{14}( \sqrt{12} +  \sqrt{7}) -\sqrt{3}( \sqrt{12} +  \sqrt{7}  )

Extract the perfect squares to get:

\sqrt{14}(2 \sqrt{3} +  \sqrt{7}) -\sqrt{3}( 2\sqrt{3} +  \sqrt{7}  )

Expand further to get;

2 \sqrt{42} +7  \sqrt{2}- 2(3)   - \sqrt{21}

This simplifies to,

2 \sqrt{42} +7  \sqrt{2}- 6- \sqrt{21}

5 0
3 years ago
Help!
Sergeu [11.5K]

Incomplete question.  

7 0
3 years ago
Determine the area of the circular floor space inside the igloo, given the walls were 0.3m thick
Vanyuwa [196]
More details are required.
8 0
3 years ago
A single​ 6-sided die is rolled twice. The set of 36 equally likely outcomes is​ {(1,1), (1,2),​ (1,3), (1,4), left parenthesis
Dennis_Churaev [7]

Answer:

The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

Step-by-step explanation:

Given : A single​ 6-sided die is rolled twice.

To find : The probability of getting two numbers whose sum is greater than 9 and less than 13 ?

Solution :

The set of 36 equally likely outcomes,

          1              2              3              4               5             6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Getting two numbers whose sum is greater than 9 and less than 13

The favorable outcome is (4,6),(5,5),(5,6),(6, 4),(6, 5),(6, 6) = 6

The probability is given by,

\text{Probability}=\frac{\text{Favorable Outcome}}{\text{Total Outcome}}

\text{Probability}=\frac{6}{36}

\text{Probability}=\frac{1}{6}

Therefore, The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

5 0
4 years ago
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