Answer:
42.1
Step-by-step explanation:
The height of the main triangle is,
h = 47√3/2 (since it's an 30-60-90 triangle)
so to find x,
tan(44) = h/x
x = h/tan(44)
x = 42.1 (rounded to the nearest tenth)
Answered by GAUTHMATH
Answer:
Angle A must be acute.
Explanation:
Both angle A and C must be acute. The sum of the angles in a triangle is 180°.
An obtuse angle is more than 90°, so the sum of the remaining 2 angles has to be less than 90°.
Note that it is impossible to have:
<span>2 right angles in a triangle, because <span>90°+90°=180</span>° and the third angle still needs to be added.1 obtuse and 1 right angle in a triangle, their sum is more than 180°2 obtuse angles in a triangle, their sum is more than 180°</span>
It is possible to have an obtuse-angled isosceles triangle, but the vertex angle must be obtuse and the equal base angles will be acute.
<span>The function h(t) = 210 – 15t has the slope-intercept form of the equation of a straight line. The y-intercept represents the amount h at the very beginning (when t=0). The negative slope (-15) represents the amount by which h will decrease if t is increased by 1.
We are manipulating the value of time, t, so time, t, is the independent variable, and h(t) = y is the dependent variable.</span>
<span>Consider the remainder of the division of the power exponent of i by 4.
For a remainder r equal to 0, 1, 2 or 3, we have a power equal to 1, i, -1 or -i respectively, therefore:
</span>





Answer:

<span>
</span>
Check the picture below.
so, as you can see, the UV segment is parallel to ZW, and therefore, they're the same slope, hmmm wait just a second, what is the slope of ZW anyway?

since now we know the ZW slope, we also know what is the slope for UV, thus,