Answer:
Step-by-step explanation:
You need to use vertex form of a quadratic to solve this.
Consider the vertex to be ![(h,k)](https://tex.z-dn.net/?f=%28h%2Ck%29)
Another way of representing a quadratic is in "vertex form":
![f(x) = a(x-h)^2+k](https://tex.z-dn.net/?f=f%28x%29%20%3D%20a%28x-h%29%5E2%2Bk)
Now all you have to do is solve for a. You know that the vertex is
and you have know the point of
. Now, all you have to do is plug in these values and solve for a.
![8 = a(1-0)^2+2\\8=a(1)^2+2\\8=a+2\\a=6](https://tex.z-dn.net/?f=8%20%3D%20a%281-0%29%5E2%2B2%5C%5C8%3Da%281%29%5E2%2B2%5C%5C8%3Da%2B2%5C%5Ca%3D6)
Now you know the equation is
, but you need it in quadratic form. All you have to do is solve is distribute the 6:
![6x^2+2](https://tex.z-dn.net/?f=6x%5E2%2B2)
You get:
a = 6
b = 0
c = 2
Please mark this as brainliest if it satisfies your question
Perimeter is 2 times the length plus 2 times the width.
Area is length times width.
Perimeter = (2 x 20) + (2 x 15) = 40 + 30 = 70 inches.
Area = 20 x 15 = 300 square inches.