Answer:
3.141592658
Step-by-step explanation:
To solve you need to set the equation equal to 6 (the height at which the player caught the ball.
6 = -16t^2 + 70t + 4
Next put the equation in standard form by subtracting 6 from both sides
-16t^2 + 70t - 2 = 0
This equation can be simplified by dividing by 2
-8t^2 + 35t - 1 = 0
This equation cannot be factored, but we can use the quadratic formula to find a value for x. Using the equation above we can find the values for a=-8, b = 35 and c = -1.
using the quadratic formula we can solve for x
-b +/- sqrt(b^2 - 4ac)
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2a
The solutions are
0.03 and 4.35. as 0.03 seems an unrealistic time to hit and catch a baseball we would expect the time to be 4.35 seconds.
You have the function

.
Rewrite it in the following way:


.
This <span>function entry allows you to determine that y=96 is the horizontal asymptote and x=-8/5 is the vertical asymptote.
</span>
From the added graph of the function you can conclude that <span>the maximum number of moose that the forest can sustain at one time is 96.</span>
Answer: Correct choice is A.
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Answer:
The answer is m = 36
Step-by-step explanation:
m/4 - 66 = -57
m - 264 = -228
m = -228 + 264
m = 36