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antoniya [11.8K]
3 years ago
10

Choose the answer which gives the electron-domain geometry and molecular geometry which are both correct for CS2 . a) The electr

on-domain geometry is tetrahedral. The molecular geometry is T-shaped. b) The electron-domain geometry is linear. The molecular geometry is T-shaped. c) The electron-domain geometry is linear. The molecular geometry is bent. d) The electron-domain geometry is tetrahedral. The molecular geometry is bent. e) The electron-domain geometry is linear. The molecular geometry is linear.
Chemistry
1 answer:
Korolek [52]3 years ago
7 0

Answer:

The electron-domain geometry is linear. The molecular geometry is linear.

Explanation:

According to the valence shell electron pair repulsion theory (VSEPR), the shape of a molecule depends on the arrangement of electron pairs present on the valence shell of the central atom of the molecule. Electron pairs are arranged in such a way as to minimize repulsion between them. The electron pairs are positioned as far apart in space as possible.

In CS2, both the molecular and electron pair geometries are linear because the electron pairs and bonding groups are positioned at an angle of 180° from each other. Hence the answer.

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If 27.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 32.40 mL of 0.185 M HCl, what is the concentration of the
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Given information : Volume of HCl = 32.40 mL

32.40 mL\times \frac{1 L}{1000 mL}

Volume of HCl = 0.0324 L

Concentration of HCl = 0.185 M or 0.185 mol/L (M = mol/L)

Volume of Ca(OH)2 = 27.0 mL

27.0 mL\times \frac{1 L}{1000 mL}

Volume of Ca(OH)2 = 0.027 L

We need to find the concentration of Ca(OH)2.

To find the concentration of Ca(OH)2 we need moles and volume of Ca(OH)2.

Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}

Moles of Ca(OH)2 can be calculated using stoichiometry and volume of Ca(OH)2 is already given to us.

Step 1 : Find the moles of HCl using its given volume and concentration.

Moles = Concentration \times Volume in L

Moles = 0.185\frac{mol}{1L}\times 0.0324 L

Moles of HCl = 0.005994 mol HCl

Step 2 : We need to find moles of Ca(OH)2 using mol of HCl with the help of mole ratio.

Mole ratio are the coefficient present in front of the compound in a balanced equation.

Mole ratio of Ca(OH)2 : HCl = 1:2 ( 1 coefficient of Ca(OH)2 and 2 coefficient of HCl)

(0.005994 mol HCl)\times \frac{(1 mol Ca(OH)2)}{(2 mol HCl)}

Moles of Ca(OH)2 = 0.002997 mol Ca(OH)2

Step 3 : Find the concentration of Ca(OH)2 using its moles and volume.

Concentration (Molarity) = \frac{(Moles of Ca(OH)2)}{(Volume of Ca(OH)2)}

Moles of Ca(OH)2 = 0.002997 mol and volume of Ca(OH)2 = 0.027 L

Concentration (Molarity) = \frac{(0.002997 mol)}{(0.027 L)}

Concentration of Ca(OH)2 = 0.111 mol/L or 0.111 M


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