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Kryger [21]
2 years ago
12

n a system for separating gases a tank containing a mixture of hydrogen and carbon dioxide is connected to a much larger tank wh

ere the pressure is kept very low. The two tanks are separated by a porous membrane through which the molecules must effuse. If the initial partial pressures of each gas is 5.00 atm, what will be the mole fraction of hydrogen in the tank after the partial pressure of carbon dioxide has declined to 4.50 atm
Chemistry
1 answer:
Stella [2.4K]2 years ago
4 0

Answer:

The mol fraction of the hydrogen gas = 0.526

Explanation:

Step 1: data given

mixture of hydrogen and carbon dioxide

the initial partial pressures of each gas is 5.00 atm

the partial pressure of carbon dioxide has declined to 4.50 atm

Step 2: Calculate total pressure

Total pressure = 4.5 atm + 5.0 atm

Total pressure = 9.5 atm

Step 3: Calculate mol fraction

Partial pressure = mole fraction * total pressure

Mol fraction = partial pressure / total pressure

Mol fraction carbon dioxide = 4.5 atm / 9.5 atm

Mol fraction carbon dioxide =  0.474

Mol fraction of hydrogen = 1 - 0.474 = 0.526

The mol fraction of the hydrogen gas = 0.526

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EleoNora [17]

The question is incomplete, the complete question is:

When heat is applied to 80 grams of CaCO3, it yields 39 grams of CaO Determine the percentage of the yield.

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<u>Answer:</u> The % yield of the product is 87.05 %

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

We are given:

Given mass of CaCO_3 = 80 g

Molar mass of CaCO_3 = 100 g/mol

Putting values in equation 1, we get:

\text{Moles of }CaCO_3=\frac{80g}{100g/mol}=0.8mol

For the given chemical reaction:

CaCO_3\rightarrow CaO+CO_2

By stoichiometry of the reaction:

If 1 mole of CaCO_3 produces 1 mole of CaO

So, 0.8 moles of CaCO_3 will produce = \frac{1}{1}\times 0.8=0.8mol of CaO

We know, molar mass of CaO = 56 g/mol

Putting values in above equation, we get:

\text{Mass of CaO}=(0.8mol\times 56g/mol)=44.8g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ......(2)

Given values:

Actual value of the product = 39 g

Theoretical value of the product = 44.8 g

Plugging values in equation 2:

\% \text{yield}=\frac{39 g}{44.8g}\times 100\\\\\% \text{yield}=87.05\%

Hence, the % yield of the product is 87.05 %

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2 years ago
The pK of acetic acid is pK = 4.76. For a 0.1 M solution of acetic acid at a pH = 4.76 what is the concentration of [H+]?
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Therefore, given the pH,  all we have to do is  solve algebraically for  [H+] :

[H+]  = antilog ( -pH ) =  10^-4.76 = 1.74 x 10⁻⁵

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3 years ago
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