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3 years ago

Which expression is equivalent to 4^6 x 4^ -8

Mathematics

1 answer:

vesna_86 [32]3 years ago

4 0

4^{-2} is the simplified version, exponents add or subtract when multipled, and the answer is .0625

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For what value of x is 1/2 x = -9 x = 18 x= -4 x=-18 x= -36

Luda [366]

Answer:

x = -18

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other.

Multiply 2 to both sides:

(x/2) * 2 = (-9) * 2

x = -9 * 2

x = -18

x = -18 is your answer.

4 0

3 years ago

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A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2

Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is $\frac{1}{20000}$

Probability of getting second prize is $\frac{2}{20000}$

Probability of getting third prize is $\frac{20}{20000}$

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

$\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10$

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is $\frac{19977}{20000}$

The expected value is

$E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25$

$E=\frac{1000+600+200-4994.25}{20000}$

$E=\frac{-3194.25}{20000}$

$E=-0.159$

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0

3 years ago

50-0 ———(12.0-0) +0 = 12.0-0 Just a warm up

vagabundo [1.1K]

$\frac{50}{12}$ x 12

the 12 in the numerator (top) and the 12 in the denominator (bottom) cross out so you are left with 50.

Answer: 50

8 0

3 years ago

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What is 6 divided by 39?

melomori [17]

6 with a remander of 3

4 0

3 years ago

A number picked at random from the numbers 1 through 15 is prime. This "question" is on my study guide for Unit 6 Probability an

Sphinxa [80]

Solution:

we are given that

A number picked at random from the numbers 1 through 15 is prime.

As we know the number between 1 and 15 which are primes are listed below

2,3,5,7,11,13.

Here total number of favourable outcomes are 6.

The numbers 1 through 15 are as below:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15.

Here total number of possible outcoes are 15.

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime $=\frac{6}{15}=\frac{2}{5}=0.40$

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime is 0.4

6 0

3 years ago

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